All categories

3 years ago

Which statement about scientific notation is true?

Chemistry

1 answer:

vladimir2022 [97]3 years ago

8 0

Explanation:

the proper format for scientific notation the following conditions must be true

You might be interested in

Explain, in full sentences, in terms of heat transfer (what type of heat transfer /how do you know?) AND specific heat (why copp

Hatshy [7]

Yes copper and the data in the table

5 0

3 years ago

The ΔHvap of a certain compound is 49.09 kJ·mol–1 and its ΔSvap is 53.69 J·mol–1·K–1. What is the boiling point of this compound

rusak2 [61]

Hey there !

Convert Joule to KJ :

1 j ---------------- 0.001 kj
53.69 j ----------- Kj

Kj = 53.69 * 0.001

=> 0.05369 Kj

T = ΔH / ΔS

T = 49.09 / 0.05369

T = 914.32ºC

3 0

3 years ago

The message that a neuron carries

Vinvika [58]

The message that a neuron carries is the nerve. This gives a signal and acts as a nerve.

6 0

3 years ago

Write a balenced chemical equation for the reaction: include abbreviation for the physical states-

WITCHER [35]

Answer:

MgBr(aq) + (NH4)3PO4(aq) -------> NH4Br(aq) + Mg3(PO4)2(s)

Explanation:

4 0

3 years ago

Gaseous ethane will react with gaseous oxygen to produce gaseous carbon dioxide and gaseous water . Suppose 2.7 g of ethane is m

Bond [772]

Answer:

$m_{H_2O}=4.86gH_2O$

Explanation:

Hello,

In this case, the described chemical reaction is:

$C_2H_6+\frac{7}{2} O_2\rightarrow 2CO_2+3H_2O$

Thus, for the given reacting masses, we must identify the limiting reactant for us to determine the maximum mass of water that could be produced, therefore, we proceed to compute the available moles of ethane:

$n_{C_2H_6}=2.7gC_2H_6*\frac{1molC_2H_6}{30gC_2H_6} =0.09molC_2H_6$

Next, we compute the moles of ethane consumed by 13.0 grams of oxygen by using the 1:7/2 molar ratio between them:

$n_{C_2H_6}^{consumed\ by \ O_2}=13.0gO_2*\frac{1molO_2}{32gO_2}*\frac{1molC_2H_6}{\frac{7}{2} molO_2}=0.116molC_2H_6$

Thus, we notice there are less available moles of ethane, for that reason, it is the limiting reactant, thereby, the maximum amount of water is computed by considering the 1:3 molar ratio between ethane and water:

$m_{H_2O}=0.09molC_2H_6*\frac{3molH_2O}{1molC_2H_6} *\frac{18gH_2O}{1molH_2O} \\\\m_{H_2O}=4.86gH_2O$

Best regards.

3 0

3 years ago