What type of intermolecular forces exist between br2 and ccl4?

Is [Ni(CO)4] considered as coordination compounds?

Harlamova29_29 [7]

Nickel carbonyl (IUPAC name: tetracarbonylnickel) is the organonickel compound

7 0

2 years ago

A sample of oxygen occupies a volume of 150 cm3 at 72 C. What will be volume of oxygen when the temperature drops to 2 C?

Ksenya-84 [330]

Answer:

V₂ = 119.59 cm³

Explanation:

Given data:

Initial volume = 150 cm³

Initial temperature = 72°C

Final volume = ?

Final temperature = 2°C

Solution:

Initial temperature = 72°C (72 +273.15 K = 345.15 K)

Final temperature = 2°C (2 + 273.15 k = 275.15 K)

Solution:

According to the Charles Law.

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁

V₂ = 150 cm³ × 275.15 K /345.15 K

V₂ = 41272.5 cm³.K / 298 K

V₂ = 119.59 cm³

8 0

2 years ago

Read 2 more answers

What are the products of the balanced equation for the combustion of C8H17OH ?

erastova [34]

C8H17OH + 12O2 —> 8CO2 + 9H2O

3 0

2 years ago

An ideal gas originally at 0.85 atm and 66°C was allowed to expand until its final volume, pressure, and temperature were 94 mL,

svet-max [94.6K]

Answer : The initial volume was, 71.2 mL

Explanation :

To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law.

The equation follows:

$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$

where,

$P_1,V_1\text{ and }T_1$ are the initial pressure, volume and temperature of the gas

$P_2,V_2\text{ and }T_2$ are the final pressure, volume and temperature of the gas

We are given:

$P_1=0.85atm\\V_1=?\\T_1=66^oC=[66+273]K=339K\\P_2=0.60atm\\V_2=94mL\\T_2=43^oC=[43+273]K=316K$

Now put all the given values in above equation, we get:

$\frac{0.85atm\times V_1}{339K}=\frac{0.60atm\times 94mL}{316K}$

$V_1=71.2mL$

Therefore, the initial volume was, 71.2 mL

4 0

3 years ago

Solid mixture contains MgCl2 and NaCl. When 0.5000 g of this solid is dissolved in enough water to form 1.000 L of solution, the

aksik [14]

Answer:

83,40 (w/w) %

Explanation:

The osmotic pressure (π) is defined as:

π = iMRT

Where i is Van't Hoff factor (3 for MgCl₂ and 2 for NaCl), M is molarity, R is gas contant (0,082atmL/molK) and T is temperature (298,15K)

iM = π / RT

iM = 0,01607mol/L

It is possible to write:

3x+2y = 0,01607mol/L (1)

Where x are moles of MgCl₂ and y moles of NaCl.

-M = moles of each compund because M is molarity (moles/L) and there is 1,000L-

Knowing molar mass of MgCl₂ is 95,2 g/mol and for NaCl is 58,44g/mol:

x×95,211 + y×58,44 = 0,5000g (2)

Replacing (2) in (1):

3x+2(0,0086 - 1,629x) = 0,01607mol/L

-0,258x = -0,00113

x = 0,004380 moles of MgCl₂

In grams:

0,004380 moles of MgCl₂×(95,211g/mol) = 0,417g of MgCl₂

Mass percent is:

(0,4170g of MgCl₂/0,5000g of solid) ×100 = 83,40 (w/w) %

I hope it helps!

4 0

2 years ago