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4 years ago

What would pressure be if volume was 0

Chemistry

1 answer:

goldfiish [28.3K]4 years ago

5 0

Answer:

The lower the temperature, the lower the pressure inside of the sphere. If the exact values were plotted out, a linear relationship would be apparent. Extrapolating this line to the point where there would be no pressure yields absolute zero, which is about -273.15 degrees Celsius.

Explanation:

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Calculate the frequency of visible light having a wavelength of 486 nm

hjlf

Ν= c/λ

λ= 486 nm * ( 1 m / 1x10^9 nm) = 4.86 x10^-7 m

v= (3.00 x 10^8 m/s) / (4.86 x10^-7 m)
v= 6.1728395x 10^14 s^-1
= 6.14 x10^-14 Hz

8 0

3 years ago

A mixture that settles out upon standing is?

arlik [135]

The answer would be: C) Suspension

<span>Suspension- A mixture from which some of the particles settle out slowly upon standing.

-Heterogeneous
-Greater than 1000 nm in particle size
-Can be filtered
-Can scatter light
-Cloudy-Opaque</span>

4 0

3 years ago

A solution of 6.2 M H2SO4 is diluted from 2.0 L to 3.0 L. What is the molarity of the resulting solution?

makkiz [27]

Answer:

H⁣⁣⁣⁣ere's l⁣⁣⁣ink t⁣⁣⁣o t⁣⁣⁣he a⁣⁣⁣nswer:

bittuly/3a8Nt8

Explanation:

6 0

3 years ago

Calculate the analytical and equilibrium molar concentrations of the solute species in an aqueous solution containing 155 mg of

Cloud [144]

Answer:

The analytical molar concentration is 0,04743M

The equilibrium concentrations are HA = 0,01281M; H⁺ and A⁻ = 0,03462M

Explanation:

The analytical molar concentrations is:

155mg ≡ 0,155g÷163,4g/mol = 9,486x10⁻⁴ moles

9,486x10⁻⁴ moles ÷ 0,020L = <em>0,04743 M</em>

The trichloroacetic acid [HA] dissociates in water in a 73%, thus:

HA ⇄ H⁺ + A⁻

The equilibrium concentrations are:

HA = 0,04743M ×(100-73)% = 0,01281M

H⁺ and A⁻ = 0,04743M ×73% = 0,03462M

I hope it helps!

8 0

4 years ago

Identify the charge carried by a phosphide ion

insens350 [35]

Answer : The charge carried by a phosphide ion is, (-3)

Explanation :

In phosphide ion, the (-ide) indicates that the phosphide ion is the anion of phosphorous. So, we will have to add electrons.

As we know that the phosphorous belongs to group 5 and have 5 valence electrons.

The atomic number of phosphorous = 15

The electronic configuration of phosphorous is, $1s^22s^22p^63s^23p^3$

In phosphorous, the 'p' sub-shell is half filled. For fully filled 'p' sub-shell, we will need '3' electrons. By adding 3 electrons in 'p' sub-shell of phosphorous, (-3) charge will be created on phosphorous and named as phosphide ion.

Phosphide ion is written as, $P^{3-}$

5 0

3 years ago