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Ann [662]
3 years ago
14

Which was the first object made by humans to orbit earth?

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

The first human made object made to orbit earth was the Soviet Union's Sputnik 1, it launched the 4th of October 1957.

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PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!
emmainna [20.7K]

Bar magnets have 2 poles. I think. Answer: first choice

6 0
3 years ago
Read 2 more answers
Suppose you performed the experiment in atmosphere of Argon at 25 deg. C, (viscosity of argon is 2.26X10^-5 N.s/m^2 at that temp
yuradex [85]

Answer:

2*10^9electrons

Explanation:

Remember that the net force will be zero at terminal voltege so

Mg = 6πrng

At 35v

We have

qvr = 6πrng

q= 6 x 3.142* nx 2.6*10^-5/35

q,= 3.2x 10^ - 10C

So using n= q/e

= 3.2x 10^ - 10C/1.6*10-19

= 2*10^9electrons

7 0
3 years ago
If the wavelength of a wave is 2.5 m, and its frequency is 3 Hz, what is its speed?
castortr0y [4]
7.5m/s (2.5 x 3) c = frequency x wavelength
3 0
3 years ago
1. Two charges Q1( + 2.00 μC) and Q2( + 2.00 μC) are placed along the x-axis at x = 3.00 cm and x=-3 cm. Consider a charge Q3 of
Masja [62]

Answer:

speed when it reaches y = 4.00cm is

v = 14.9 g.m/s

Explanation:

given

q₁=q₂ =2.00 ×10⁻⁶

distance along x = 3.00cm= 3×10⁻²

q₃= 4×10⁻⁶C

mass= 10×10 ⁻³g

distance along y = 4×10⁻²m

r₁ = \sqrt{3^{2} +2^{2}  } = \sqrt{13} = 3.61cm = 0.036m

r₂ = \sqrt{4^{2} + 3^{2}  } = \sqrt{25} = 5cm = 0.05m

electric potential V = \frac{kq}{r}

change in potential ΔV = V_{1} - V_{2}

ΔV = \frac{2kq_{1} }{r_{1}} - \frac{2kq_{2} }{r_{2} } , where q_{1} = q_{2}=2.00μC

ΔV = 2kq(\frac{1}{r_{1}} - \frac{1}{r_{2} })

ΔV = 2 × 9×10⁹ × 2×10⁻⁶ × (\frac{1}{0.036} - \frac{1}{0.05} )

ΔV= 2.789×10⁵

\frac{1}{2}mv^{2} = ΔV × q₃

\frac{1}{2} ˣ 10×10⁻³ ×v² = 2.789×10⁵× 4 ×10⁻⁶

v² = 223.12 g.m/s

v = 14.9 g.m/s

3 0
3 years ago
"Sarah is out playing fetch with her dog, and throws a tennis ball as far as she can. At the moment the ball reaches its maximum
e-lub [12.9K]

Answer:

<h2>a.The ball's vertical acceleration is downwards.</h2><h2>e.The ball's horizontal acceleration is zero</h2>

Explanation:

We are given that Sarah throws a tennis ball as far as she can.

At the moment the ball reaches its maximum height.

We have to find the true statement if air resistance is neglect.

When air resistance is negligible then the force act on the ball is force due to gravity.

The ball throw vertically then the acceleration act on the ball is acceleration due to gravity.

The value of g=-9.8 m/square sec

It acts on the ball in downward direction .

Therefore, the ball's vertical acceleration is downwards.

The horizontal acceleration is zero because the ball reaches at maximum height then there is no force which act in horizontal direction on the ball.

Therefore, horizontal acceleration of the ball is zero.

Hence, option a and e are true.

3 0
3 years ago
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