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Ann [662]
3 years ago
14

Which was the first object made by humans to orbit earth?

Physics
1 answer:
Romashka-Z-Leto [24]3 years ago
6 0

The first human made object made to orbit earth was the Soviet Union's Sputnik 1, it launched the 4th of October 1957.

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What is the deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h? (such deceleration caused on
Wewaii [24]

The deceleration of the rocket sled if it comes to rest in 1.1 s from a speed of 1000 km/h is  252.52\ m/s^2.

The acceleration in opposite direction is known as the deceleration. Basically the deceleration is negative value of the acceleration since the negative sign depicts its opposite in direction.

The given data:

time, t = 1.1 s

initial speed, u = 1000 km/h = \frac{2500}{9}\ m/s

final speed, v = 0 m/s

So we will be using the equation of motion, that is,

v = u + at

\therefore 0=\frac{2500}{9} + a(1.1)

\Rightarrow a=-\frac{2500}{9(1.1)}

\therefore a = - 252.52 \ m/s^2

Hence , the deceleration of the rocket is  252.52\ m/s^2.

To learn more about Attention here:

brainly.com/question/28500124

#SPJ4

6 0
2 years ago
A truck moving at 36 m/s passes a police car moving at 45 m/s in the opposite direction. If the frequency of the siren is 500 Hz
wariber [46]

Answer:

change in frequency is 636 Hz

Explanation:

given data

speed v1 = 36 m/s

speed v2 = 45 m/s

frequency f = 500 Hz

speed of sound s = 343 m/s

to find out

what is the change in frequency

solution

we know here change of frequency formula that is

frequency = \frac{s+v1}{s+v2} (f)   ...................1

put here value in equation 1

and we take v2 = -45 because opposite direction

frequency = \frac{s+v1}{s-v2} (f)

frequency = \frac{343+36}{343-45} (500)

frequency = 636

so change in frequency is 636 Hz

8 0
4 years ago
A person lifts a 6.50kg box off the ground a vertical distance of 1.25m and then carries it horizontally across the room by 4.75
victus00 [196]
What type of reaction is being shown in this energy diagram
6 0
3 years ago
In a warehouse, the workers sometimes slide boxes along the floor to move them. Two boxes were sliding toward each other and cra
san4es73 [151]

Answer:

Box 1 has more mass than box 2.

Explanation:

Box 1 has more mass than box 2, as it caused a greater affect in the change of speed of box 2. During a collision, the object with a lesser mass will be affected more, causing the velocity to change more. Because box one is greater than box  2, it caused a larger change in speed when they collided.

3 0
3 years ago
The figure above represents a stick of uniform density that is attached to a pivot at the right end and has equally spaced marks
zavuch27 [327]

Answer:

After 2.0s the  angular momentum is L= 2(4A+3B+2C+D)x

Explanation:

Let us call forces acting on the rod, A, B, C, and D, and the separation between them x .

Then, the  torque due to force A is

\tau_a = 4Ax,

due to the force B

\tau_b = 3Bx,

due to force C

\tau_c = 2Cx,

and the torque due to force D is

\tau_d = Dx.

Therefore, the total torque on the the stick is

\tau_{tot} =\tau_a+\tau_b+\tau_c+\tau_d

\tau_{tot} =4Ax+3Bx+2Cx+Dx

\tau_{tot} =x(4A+3B+2C+D)

Now, this torque causes angular acceleration \alpha according to the equation

I \alpha = \tau_{tot}

where I is moment of inertia of the stick and it has the value

I = \dfrac{1}{3} m(4x)^2

Therefore the angular acceleration is

\alpha = \dfrac{\tau_{tot} }{I}

\alpha =\dfrac{x(4A+3B+2C+D)}{\dfrac{1}{3}m(4x)^2 }

\boxed{\alpha =\dfrac{3(4A+3B+2C+D)}{16mx } .}

Now, the angular momentum L of the stick is

L = I\omega,

where \omega is the angular velocity.

Since \omega = \alpha t, we have

$L = \dfrac{1}{3}m (4x)^2  *\dfrac{3(4A+3B+2C+D)}{16mx }* t$

L= (4A+3B+2C+D)x t

Therefore,   t = 2.0s, the angular momentum is

\boxed{ L= 2(4A+3B+2C+D)x. }

5 0
3 years ago
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