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3 years ago

The planet most noted for its rings is

Physics

1 answer:

svlad2 [7]3 years ago

4 0

Saturn, it is known as the planet with rings around it

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True or False:

mart [117]

This is a true statement

3 0

3 years ago

Read 2 more answers

You are measuring the volume of a chemical beaker how would u take the measurment?

8090 [49]

I think its d because lifting it would make the chemical swish around and that will make it so you cant get the right measurement. hope this helps :)

6 0

3 years ago

A flat coil of wire consisting of 20 turns, each with an area of 50 cm2, is positioned perpendicularly to a uniform magnetic fie

jenyasd209 [6]

Answer:

0.5 A

Explanation:

N = 20, A = 50 cm^2 = 50 x 10^-4 m^2, dB = 6 - 2 = 4 T, dt = 2 s, R = 0.4 ohm

The induced emf is given by

e = - N dФ/dt

Where, dФ/dt is the rate of change of magnetic flux.

Ф = B A

dФ/dt = A dB/dt

so,

e = 20 x 50 x 10^-4 x 4 / 2 = 0.2 V

negative sign shows the direction of magnetic field.

induced current, i = induced emf / resistance = 0.2 / 0.4 = 0.5 A

5 0

3 years ago

5. Each of five satellites makes a circular orbit about an object that is much more massive than any of the satellites. The mass

Vikentia [17]

The options of the question are missing. I have attached it.

Answer:

Satellite in option B will have the greatest speed.

Explanation:

From kepplers third law, we know that

V² = GM/R

Thus, v = √(GM/R)

Where;

v is velocity

G is gravitational constant

M is mass

R is radius

Looking at the options, let's start from the first one;

Option A

Here, mass = (1/2)m and radius = R

So, v = √(GM/R) thus v = √(G(m/2)/R) = √(Gm/2R)

Option B

Here, mass = m and radius = (1/2)R

Thus v = √(Gm/(R/2)) = √(2Gm/R)

Option C

Here, mass = m and radius = R

Thus v = √(Gm/R)

Option D

Here, mass = m and radius = 2R

Thus v = √(Gm/(2R))

Now, inspecting all the options, it's clear that option B will have the greatest velocity because it's numerator is the biggest and will in turn lead to higher velocity.

4 0

3 years ago

The Atwood machine consists of two masses hanging from the ends of a rope that passes over a pulley. Assume that the rope and pu

Kisachek [45]

Answer:

$a=2.36\ m/s^2$

T=157.06 N

Explanation:

Given that

Mass of first block = 21.1 kg

Mass of second block = 12.9 kg

First mass is heavier than first that is why mass second first will go downward and mass second will go upward.

Given that pulley and string is mass less that is why both mass will have same acceleration.So lets take their acceleration is 'a'.

So now from force equation

$m_1g-m_2g=(m_1+m_2)a$

21.1 x 9.81 - 12.9 x 9.81 =(21.1+12.9) a

$a=2.36\ m/s^2$

Lets tension in string is T

$m_1g-T=m_1a$

$T=m_1(g-a)$

T=21.1(9.81-2.36) N

T=157.06 N

6 0

3 years ago