Answer:
So Nessa went so fast it made her pass the tile in a second. Lets take a look at this problem, It says "the" tile so we should assume that it means 1 tile. Then draw a diagram representing that tile then you should have your problem finished. Hope that helped and I'm willing to help if you have anymore questions!
Explanation:
Answer:
t = 47 years
Explanation:
To find the number of years in which the electrons cross the complete transmission, you first calculate the drift velocity of the electrons in the transmission line, by using the following formula:
(1)
I: current = 1,010A
A: cross sectional area of the transmission line = π(d/2)^2
d: diameter of the transmission line = 2.00cm = 0.02 m
n: free charge density = 8.50*10^28 electrons/m^3
q: electron's charge = 1.6*10^-19 C
You replace the values of all parameters in the equation (1):

with this value of the drift velocity you can calculate the time that electrons take in crossing the complete transmission line:

Finally, you convert this value of the time to years:

hence, the electrons take around 47 years to cross the complete transmission line.
By adding the time of flight at the top of the cliff and the time taken down the hill, the ball spent 2.72 s of time in air.
<h3>
What is a Projectile ?</h3>
A projectile can be a stone or a ball or any object that can be projected. The object projected will take a trajectory path.
Given that acceleration due to gravity is 9.8 m/s and a 0.87 kg projectile is fired into the air from the top of a 8.52 m cliff above a valley. Its initial velocity is 9.1 m/s at 49◦ above the horizontal. To know how long the projectile will be in the air, we will calculate the total time of flight at the top of the cliff and the time taken down the hill
Time of flight T = 2usinФ/g
Where
Substitute all the necessary parameters into the formula
T = (2 × 9.1sin49)/ 9.8
T = 13.74/9.8
T = 1.40 s
The time taken down the cliff can be found with formula
h = ut + 1/2gt²
where u = 0
8.52 = 0 + 1/2 × 9.8 × t²
8.52 = 4.9t²
t² = 8.52/4.9
t² = 1.738
t = √1.738
t = 1.32 s
Time for the projectile in the air = T + t
Time in air = 1.40 + 1.32
Time = 2.72 s
Therefore, the projectile will be in the air for 2.72 seconds long.
Learn more about Projectile here: brainly.com/question/24949996
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Answer:
A)

B)

Explanation:
A)
= magnitude of charge on each sphere = 
= Distance between the two spheres = 10 cm = 0.10 m
= magnitude of force between the two spheres
Using Coulomb's law, magnitude of the force between two charged sphere

B)
= mass of the sphere =
= Force of gravity in down direction = 
= Electrostatic force of repulsion in upward direction = 
= acceleration of the sphere
Force equation for the motion of the sphere is given as

To solve this problem it is necessary to apply the Snell Law. With which the angles of refraction and incidence on two materials with a determined index of refraction are described.
The equation stipulates that

Where,
= Index of refraction of each material
Angle of incidence or Angle of Reflection
Angle of refraction
Our values are given as,
Index of refraction of water


Replacing we have that,




Therefore the angle of reflection is 20.93°