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steposvetlana [31]
3 years ago
11

How does a compass needle respond when a compass is placed within a magnetic field? It aligns in a direction parallel to the fie

ld. It points toward the edge of the field. It rotates in the center of the field. It aligns in a direction perpendicular to the field.
Physics
2 answers:
Maksim231197 [3]3 years ago
8 0

When a compass is placed within a magnetic field, it aligns in a direction <em>parallel to the field</em>.

agasfer [191]3 years ago
6 0

At the point when a compass is put inside an attractive field, it adjusts toward a path parallel to the field.

Hope this helps ^_^

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Arturiano [62]

Answer:

The velocity is  v_2 =  6.8 \ m/s

The pressure is  P_2 =  204978 Pa

Explanation:

From the question we are told that

 The speed at which water is travelling through is  v = 1.7 \ m/s

  The pressure is  P_1 = 205  k  Pa =  205 *10^{3} \ Pa

   The diameter of the new pipe is d =  \frac{D}{2}

Where D is the diameter of first pipe

   

According to the principal of continuity we have that

       A_1 v_1 =  A_2 v_2    

Now  A_1 is the area of the first pipe which is mathematically represented as

       A_1 = \pi  \frac{D^2}{4}

and  A_2 is the area of the second pipe which is mathematically represented as  

       A_2 = \pi  \frac{d^2}{4}

Recall   d =  \frac{D}{2}

        A_2 = \pi  \frac{[ D^2]}{4 *4}

        A_2 = \frac{A_1}{4}

So    A_1 v_1 =  \frac{A_1}{4}  v_2

substituting value

        1.7 =  \frac{1}{4}  * v_2    

        v_2 =  4 * 1.7    

       v_2 =  6.8 \ m/s

   

According to Bernoulli's equation  we have that

     P_1 + \rho \frac{v_1 ^2}{2} =  P_2 + \rho \frac{v_2 ^2}{2}

substituting values

     205 *10^{3 }+ \frac{1.7 ^2}{2} =  P_2 +  \frac{6.8 ^2}{2}

     P_2 =  204978 Pa

4 0
3 years ago
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