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3 years ago

The weight of a body is 600 N. What is the mass of the body on the surface of the earth?

Physics

2 answers:

mamaluj [8]3 years ago

7 0

Explanation:

soln,

weight=600N

mass=?

gravity=9.8 m/s²

now,

mass=weight/gravity
mass=600/9.8
mass=61.22kg

hope it helps.

<h2>stay safe healthy and happy.</h2>

matrenka [14]3 years ago

5 0

Answer:

m = 61.22 kg

Explanation:

F = 600 N

g = 9.8 m/s²

m = ?

F = mg

600 = m(9.8)

---> m = 61.22 kg

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Water is flowing at 4.0 m/s in a circular pipe. If the diameter of the pipe decreases to 1/2 of its former value, what is the ve

Montano1993 [528]

Answer:

v₂ = 16 m/s

Explanation:

We can use the continuity equation, which is as follows:

$A_1v_1 = A_2v_2\\$

where,

A₁ = Area of inlet = πd²/4

A₂ = Area of outlet = π(d/2)²/4 = πd²/16

v₁ = velocity at inlet = 4 m/s

v₂ = velocity at outlet = ?

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$(\frac{\pi d^2}{4})(4\ m/s)=(\frac{\pi d^2}{16})v_2\\\\$

v₂ = 16 m/s

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3 years ago

Supply the missing force necessary to achieve equilibrium. Show your work.

Mumz [18]

Analysing the Question:

We know that equilibrium is the state of a body when it has equal and opposite forces being applied on it

In this case, a net downward force of 496N is being applied and a net upward force of (106 + 106 + 142 + x) N

Finding the missing force:

Since we have to achieve equilibrium, the net upward forces have to be equal to the net downward forces

So, (106 + 106 + 142 + x) = 496

354 + x = 496

x = 496 - 354

x = 142 N

Therefore, the missing force is 142 N

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3 years ago

Please help, What does a Transverse and longitude wave combine to form?

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Electromagnetic waves transfer energy without going through a medium. ... Sometimes, a transverse wave and a longitudinal wave can combine to formanother kind of wave called a surface wave. Transverse Waves. Waves in which the particles vibrate in an up-and-down motion

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3 years ago

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A 2190 kg car moving east at 10.5 m/s collides with a 3220 kg car moving east. The cars stick together and move east as a unit a

Bezzdna [24]

To solve this problem it is necessary to apply the concepts related to the conservation of the Momentum describing the inelastic collision of two bodies. By definition the collision between the two bodies is given as:

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

Where,

$m_{1,2}$ = Mass of each object

$v_{1,2}$ = Initial Velocity of Each object

$V_f$ = Final Velocity

Our values are given as

$m_1 = 2190Kg$

$v_1 =10.5m/s$

$m_2 = 3220kg$

$V_f = 4.74m/s$

Replacing we have that

$m_1v_1+m_2v_2 = (m_1+m_2)V_f$

$(2190)(10.5)+(3220)v_2 = (2190+3220)(4.74)$

$v_2 = 0.8224m/s$

Therefore the the velocity of the 3220 kg car before the collision was 0.8224m/s

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4 years ago

A ball is thrown vertically upward with a speed of 18.0 m/s. (a) How high does it rise? (b) How long does it take to reach its h

Mrrafil [7]

Answer:

a) $y=16.53m$

b) $t_{up}=1.83s$

c) $t_{down}=1.84s$

d) $v=-18m/s$

Explanation:

a) To find the highest point of the ball we need to know that at that point the ball stops going up and its velocity become 0

$v^{2} =v^{2} _{o} +2g(y-y_{o})$

$0=(18)^{2} -2(9.8)(y-0)$

Solving for y

$y=\frac{(18)^{2} }{2(9.8)}=16.53m$

b) To find how long does it take to reach that point:

$v=v_{o}+at$

$0=18-9.8t$

Solving for t

$t_{up} =\frac{18m/s}{9.8m/s^{2} }= 1.83s$

c) To find how long does it take to hit the ground after it reaches its highest point we need to find how long does it take to do the whole motion and then subtract the time that takes to go up

$y=y_{o}+v_{o}t+\frac{1}{2}gt^{2}$