The equation for Kc:
Kc = [C]² / [A] [B]
Let the equilibrium concentration of C be x
Then,
the equilibrium concentration of A = 1-x
the equilibrium concentration of B = 1-x
The equation becomes:
4 = x² / (1 - x)²
3x² - 8x + 4 = 0
x = 2, x = 2/3
The first answer is not possible so x = 2/3
[A] = 1 - 2/3 = 1/3
[B] = 1 - 2/3 = 1/3
Answer:
y = L h / a √√ (2q V m)
Explanation:
This is a diffraction exercise, so we must use the D'Broglie relation to encode the wavelength of the electron beam.
p = h / λ
λ= h / p
the moment is
p = m v
λ = h / mv
Let's use energy conservation
E = K
q ΔV = ½ m v²
v = √ 2qΔv / m
λ = h / (m √2q ΔV / m)
λ = h / √ (2q ΔV m)
Having the wavelength of the electrons we can use the diffraction ratio
a sin θ = m λ
First minimum occurs for m = 1
sin θ = λ / a
let's use trigonometry for the angles
tan θ = y / x
as in these experiments the angles are very small
tan θ = sin θ / cos θ = sin θ
sin θ = y / x
we substitute
y / x = λ / a
y = x λ / a
we replace the terms
y = L h / a √√ (2q V m)
The labeled points which is Letter B in the given Image is the point that the axis of rotation passes through. This problem is an example of rotational dynamics, formerly an object moves in a straight line then the motion is translational but when an object at inactivity lean towards to continue at inactivity and an object in rotation be possible to continue rotating with continuous angular velocity unless bound by a net external torque to act then is rotational. In a rotational motion, the entity is not treated as a constituent part but is treated in translational motion. It points out with the study of torque that outcomes angular accelerations of the object.