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2 years ago

1 pts

Physics

1 answer:

mezya [45]2 years ago

4 0

Answer:

46 dgres is the answer

Explanation:

plz mark me brainliest plz Plz

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A 17-mm-wide diffraction grating has rulings of 530 lines per millimeter. White light is incident normally on the grating. What

Sedbober [7]

Answer:

377 nm

Explanation:

Number of lines per meter is, $N &=530 \times 1000 \\ &=530000 \text { lines } / \mathrm{m} \end{aligned}$

Grating element is, $d=\frac{1}{N}$

$=1.8868 \times 10^{-6} \mathrm{~m}[tex]
Order is, n=5
Condition for maximum intensity is, [tex]d \sin \theta=n \lambda$

$\lambda &=\frac{1.8868 \times 10^{-6}}{5(\sin 90)} \\
&=0.377 \times 10^{-6} \mathrm{~m} \\
&=377 \mathrm{~nm}$

7 0

3 years ago

At time t1 = 2.00 s, the acceleration of a particle in counterclockwise circular motion is (7.00 m/s2)i hat + (6.00 m/s2)j. It m

Elina [12.6K]

Answer:

r = 3519.55 m

Explanation:

We know that the acceleration of a particle in a circular motion is directed towards the center of the circumference and has magnitude:

F = rω^2

Where r is the radius of the circumference and ω is the angular velocity.

From the two acceleration vectors we find that their magnitude is

√(7^2+6^2) = √85

Therefore:

√85 m/s^2= rω^2

Now we need to calculate the angular velocity to obtain the radius. Since t2-t1 = 3s is less than one period we can be sure that the angular velocity is equals to the angle traveled between this time divided by 3 s.

The angle with respect to the x-axis for the particle at t1 and t2 is:

$\theta 1 =\cos ^{-1}\left(\frac{7}{\sqrt{85}}\right)\\\theta 2 =\cos ^{-1}\left(\frac{6}{\sqrt{85}}\right)\\$

Therefore, the angular velocity ω is (in radians per second):

$\omega = \frac{\theta2 - \theta1}{3 s} = 0.0511813 \frac{1}{s}$

Therefore:

r = √85 / (0.0511813)^2 = 3519.55 m

4 0

3 years ago

What inspired Ronald McNair to do science

Karo-lina-s [1.5K]

Answer:

While working as a staff physicist at hughes Research Laboratories McNair learned that the National Aeronautics and Space Administration (NASA) was looking for scientist to join the shuttle program;)

4 0

3 years ago

What is the name of the kind of stretch that involves stretching as far as you can and then holding for 10-30 seconds

Dmitriy789 [7]

Answer:

Static stretching.

Explanation:

It is static stretching because it is a form of stretching which u can do actively for a period of time and you hold position for about 30 to 60 seconds which allow the muscles and connective tissues to lengthen. It is done after work out with out movement in order to loosen up muscles so as to gain flexibility.

7 0

3 years ago

At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 34.7998 cm on a spring with a sprin

Otrada [13]

Answer:

W = 32.03316 N

Explanation:

given,

Amplitude, A = 34.7998 cm = 0.347998 m

spring constant, k = 13.5666 N/m

maximum speed, v = 70.8966 cm/s = 0.708966 m/s

acceleration due to gravity, g = 9.8 m/s²

weight of the banana = ?

using maximum speed formula

$v_{max} = A \sqrt{\dfrac{k}{m}}$

squaring both side

$v_{max}^2 = A^2 \dfrac{k}{m}$

$m = \dfrac{A^2k}{v_{max}^2}$

$m = \dfrac{0.347998^2\times 13.5666}{0.708966^2}$

m = 3.26868 Kg

weight

W = mg

W= 3.26868 x 9.8

W = 32.03316 N

hence, weight of Banana is equal to W = 32.03316 N

7 0

3 years ago