All categories

3 years ago

The quotient of -4/5 and 4/5

Mathematics

1 answer:

Alchen [17]3 years ago

6 0

Since they’re the same thing except for the sign, the answer is -1

You might be interested in

What is they answer on the sheet of paper for my homework

geniusboy [140]

Um not sure but thanks for asking:)

3 0

3 years ago

What is correct?

DochEvi [55]

4 °C

i just googled it XD. source: https://www.google.com/search?q=the+density+of+water+is+maximum+at+which+temperature&oq=the+density+of+water+is+maximum+at+which+temperature&aqs=chrome..69i57.699j0j4&client=ms-android-samsung&sourceid=chrome-mobile&ie=UTF-8

8 0

4 years ago

1/(x+1) + 1/a(x+1) find the lcm

azamat

Answer:

See below.

Step-by-step explanation:

1/(x + 1) consists of 1 factor, 1/(x + 1)

1/[a(x + 1)] consists of two factors, 1/a and 1/(x + 1)

The LCM is 1/[a(x + 1)]

The LCD is a(x + 1)

5 0

3 years ago

Can Someone Please Help Me With This, Thanks! :)

Murrr4er [49]

Answer:

405

Step-by-step explanation:

So he built 5/9 of the wall, than added the extra 180 bricks to finish the wall.

so 5/9 + 180 = 9/9

so 180 = 4/9 Because 5/9 + 4/9 = 9/9

So to figure out how many bricks are in the wall we want to know what 1/9 of bricks equals and to work this out we need to divide 180 by 4

which equals 45.

Now we know that 1/9 = 45

so now to figure out what 9/9 is just multiply 45 by 9 which equals 405

7 0

2 years ago

Read 2 more answers

Find the maximum and minimum values attained by f(x, y, z) = 5xyz on the unit ball x2 + y2 + z2 ≤ 1.

Allushta [10]

Check for critical points within the unit ball by solving for when the first-order partial derivatives vanish:
$f_x=5yz=0\implies y=0\text{ or }z=0$
$f_y=5xz=0\implies x=0\text{ or }z=0$
$f_z=5xy=0\implies x=0\text{ or }y=0$

Taken together, we find that (0, 0, 0) appears to be the only critical point on $f$ within the ball. At this point, we have $f(0,0,0)=0$ .

Now let's use the method of Lagrange multipliers to look for critical points on the boundary. We have the Lagrangian

$L(x,y,z,\lambda)=5xyz+\lambda(x^2+y^2+z^2-1)$

with partial derivatives (set to 0)

$L_x=5yz+2\lambda x=0$
$L_y=5xz+2\lambda y=0$
$L_z=5xy+2\lambda z=0$
$L_\lambda=x^2+y^2+z^2-1=0$

We then observe that

$xL_x+yL_y+zL_z=0\implies15xyz+2\lambda=0\implies\lambda=-\dfrac{15xyz}2$

So, ignoring the critical point we've already found at (0, 0, 0),

$5yz+2\left(-\dfrac{15xyz}2\right)x=0\implies5yz(1-3x^2)=0\implies x=\pm\dfrac1{\sqrt3}$
$5xz+2\left(-\dfrac{15xyz}2\right)y=0\implies5xz(1-3y^2)=0\implies y=\pm\dfrac1{\sqrt3}$
$5xy+2\left(-\dfrac{15xyz}2\right)z=0\implies5xy(1-3z^2)=0\implies z=\pm\dfrac1{\sqrt3}$

So ultimately, we have 9 critical points - 1 at the origin (0, 0, 0), and 8 at the various combinations of $\left(\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3},\pm\dfrac1{\sqrt3}\right)$ , at which points we get a value of either of $\pm\dfrac5{\sqrt3}$ , with the maximum being the positive value and the minimum being the negative one.

5 0

3 years ago