Answer:
26.8 inches of fabrics was used on headband and wristband for each player
Step-by-step explanation:
Headbands for 31 players and 3 couches = 611.66 inches of fabric
Total number of people = 31 players + 3 couches
= 31 + 3
= 34 people
Fabrics per person's headbands = Total inches of fabrics for headbands / total number of people
= 611.66 inches of fabric / 34 people
= 17.99 inches of fabrics per person
Wristband for 31 players = 273.11 inches of fabric
Fabric per person's wristband = total inches of fabrics for wristband / number of players
= 273.11 inches of fabric / 31
= 8.81 inches per person
How much fabric was used on a headband and wristband for each player?
= Fabrics per person's headbands + Fabric per person's wristband
= 17.99 inches + 8.81 inches
= 26.8 inches of fabrics was used on headband and wristband for each player
<span>Answer: Brian
has some understanding of budgeting. However, a budget does not create
more money each month. It just helps him use his money better.
This is what Brian said and my assessment:
</span>
<span>.... his budget helps him know where his money is
being spent TRUE
It allows him to spend some money on entertainment with
the peace of mind that he will be able to pay the rent: TRUE
...and even gives
him more money each month NOT REALLY ... money is not created by the budget</span>
Answer:
9x² − 12x + 4
Step-by-step explanation:
A perfect square trinomial:
a² + 2ab +b²= (a + b)²
a² - 2ab +b²= (a - b)²
9x² − 12x + 4 = (3x)² - 2*(3x)*2 + 2² = (3x - 2)²
36b² − 24b + 16
16x² − 24x − 9
4a² − 10a − 25
Answer:
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
Step-by-step explanation:
Hello!
Considering the dependent variable:
Y: Ductility in steel.
And the independent variable:
X: Carbon content of the steel.
The linear regression was estimated and a prediction interval was calculated.
The prediction interval is calculated to predict a value that the variable Y (response variable) can take for a given value of the variable X (predictor variable) in the definition range of the linear regression line. Symbolically [Y/X=
]
In this case 95% prediction interval for Y/X=0.5
At a level of 95%, it is expected that the interval [0.45; 11.59] contains the value of the ductility in steel when its carbon content is 0.5%.
I hope it helps!
There is 0.946 liter in 1 quart
3.5/0.946 = 3.6997
~3.7 liters, or C
C is your answer
hope this helps
