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Rina8888 [55]
3 years ago
8

If a runner completes a 10 kilometer race in 32.50 minutes, what is the 10.0 km pace in miles per hour? (1.609 km = 1 mile appro

ximately)
Chemistry
1 answer:
Elina [12.6K]3 years ago
3 0
If a runner completes a 10 km race in 32.5 minutes, his pace or speed can be calculated by the equation:

velocity = distance/time = 10km/32.5 mins = 0.3125 km/min

Convert this value to miles per hour using the conversion factors for minutes to hours and kilometers to miles as requested by the problem. This gives an answer of 11.47 miles per hour.

0.3125 km/min x 60 mins./ 1 hour x 1 mile / 1.609 km = 11.47 miles/hour
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Answer:

most likely that (2) the replicated experiment was performed incorrectly.

Why, u ask? u dare question me:

1- The initial experiment invalidness cannot be proven.

2- <em><u>t</u></em><em><u>h</u></em><em><u>e</u></em><em><u> </u></em><em><u>s</u></em><em><u>e</u></em><em><u>c</u></em><em><u>o</u></em><em><u>n</u></em><em><u>d</u></em><em><u> </u></em><em><u>a</u></em><em><u>n</u></em><em><u>s</u></em><em><u>w</u></em><em><u>e</u></em><em><u>r</u></em><em><u> </u></em><em><u>i</u></em><em><u>s</u></em><em><u> </u></em><em><u>c</u></em><em><u>o</u></em><em><u>r</u></em><em><u>r</u></em><em><u>e</u></em><em><u>c</u></em><em><u>t</u></em>

3- Different labaratories does not effect the outcome, as long as the parameter and environment of the replicated experiment is the same as when the initial experiment was conducted.

4- Already knowing the data and errors would increase the precision of the replicated experiment.

5- Change in variables should still be in the objective (or purpose) of the experiment, thus, major difference in the outcome should not happen.

happy learning!

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