Answer:
11·699
Explanation:
Given the concentration of hydroxide ion in the solution is 5 × 
M
Assuming the temperature at which it is asked to find the pH of the solution be 298 K
<h3>At 298 K the dissociation constant of water is
</h3><h3>∴ pH + pOH = 14 at 298 K</h3><h3>pOH of the solution = -log( concentration of hydroxide ion )</h3>
∴ pOH of the given solution = - log(5 × = -0·699 + 3 = 2·301
pH of the given solution = 14 - 2·301 = 11·699
∴ pH of the solution = 11·699
Hello there.
<span>A 250.0 ml buffer solution is 0.250 M in acetic acid and. 250M in sodium acetate. what is the ph after addition of. 0050 mol of HCL? what is the ph after the addition of. 0050 mol of NaOH?
Part 2 answer: </span><span>pH = 4.67 </span>
Answer:
molecules C6H12O6 = 2.674 E22 molecules.
Explanation:
from periodic table:
⇒ molecular mass C6H12O6 = ((6)(12.011)) + ((12)(1.008)) + ((6)(15.999))
⇒ Mw C6H12O6 = 180.156 g/mol
⇒ mol C6H12O6 = (8.00 g)(mol/180.156 g) = 0.0444 mol C6H12O6
∴ mol ≡ 6.022 E23 molecules
⇒ molecules C6H12O6 = (0.0444 mol)(6.022 E23 molecules/mol)
⇒ molecules C6H12O6 = 2.674 E22 molecules
Answer:
All of these are true
Explanation:
A buffer solution in chemistry is a solution that resists changes in pH when an acid or base is added to it. It is a solution that contains a weak acid and its conjugate base (anion) or a weak base and its conjugate acid.
A buffer is able to resist a change in pH due to the conjugate base and conjugate acid of the weak acids and bases contained in them respectively. The conjugate base/acid are present in an equilibrium quantity with their acid/base counterparts and help to neutralize or react with any additional H+ or OH- from an acid or base added to their solution.
However, when a strong acid or base is added to the buffer solution, there is only a slight change which practically does not change the pH of the solution.
Hence, all of the above options about a buffered solution is true.
