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DochEvi [55]
3 years ago
10

An empty parallel plate capacitor is connected between the terminals of a 4.4-V battery and charged up. The capacitor is then di

sconnected from the battery, and the spacing between the capacitor plates is quadrupled. As a result of this change, what is the new voltage between the plates of the capacitor?
I have:E = v/dE =9 Vthen the distance is doubled 9(2) = 18 V
Physics
1 answer:
torisob [31]3 years ago
7 0

Answer:

d

Explanation:

idk

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Read 2 more answers
Will award brainliest and upvote if you can help answer! ​
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I have done this before and got it correct

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