Answer:
Vx = 35 x cos(13deg)
Vy = 35 x sin(13deg) - gt
(g is acceleration due to gravity =~9.8 meter/second^2, t is time in second)
Explanation:
The tiger leaps up, then x and y component of its velocity are:
Vx = Vo x cos(alpha)
Vy = Vo x sin(alpha) - gt
(Vo is tiger's initial velocity, alpha is angle between its leaping direction and horizontal plane)
Hope this helps!
Answer:
The force of static friction acting on the luggage is, Fₓ = 180.32 N
Explanation:
Given data,
The mass of the luggage, m = 23 kg
You pulled the luggage with a force of, F = 77 N
The coefficient of static friction of luggage and floor, μₓ = 0.8
The formula for static frictional force is,
Fₓ = μₓ · η
Where,
η - normal force acting on the luggage 'mg'
Substituting the values in the above equation,
Fₓ = 0.8 x 23 x 9.8
= 180.32 N
Hence, the minimum force require to pull the luggage is, Fₓ = 180.32 N
Answer:
Explanation:
if
and g=9.81 m/s2=32.16 ft/s2
and
W=m*g
we can just replace de mass and gravity and we have
Answer:
m = 0.25
Explanation:
Given that,
Object distance, u = -15cm
Height of the object, h = 48
Focal length, f = cm
We need to find the magnification of the image.
Let v is the image distance. Using mirror's equation.
Magnification,
Hence, the magnification of the image is 0.25.
