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Vlad1618 [11]
3 years ago
14

determine whether the following equations are dimensionally correct if not how can you make them dimensionally correct 1 /2 mv2

=(mgh) 2​
Physics
1 answer:
serg [7]3 years ago
6 0

Answer:

1 /2 mv^{2} =mgh

Explanation:

The correct equation follows the law of conservation of energy where kinetic energy is all transformed to potential energy, since we know that kinetic energy is expressed as

1 /2 mv^{2} while potential energy is mgh where m is the mass of the object, v is the velocity or speed of the object, g is acceleration due to gravity and h is the vertical height. Therefore, relating the two equations we should have 1 /2 mv^{2} =mgh

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Usually, when the temperture is increased l, what will happen to the ratevof dissolving?
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3 0
3 years ago
9. A sports car travels on a straight road at 22.0 km/h and increases its speed to 57.0 km/h in
Varvara68 [4.7K]

Answer:

4.4 M/s

Explanation:

6 0
3 years ago
Please help me quickly!!!
vichka [17]
Hey! So referring to the data the thing we can clearly see is that in a vacuum, everything, regardless of its mass, falls at the same speed.

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3 years ago
At what water temperature will additional heat energy need to be added before the temperature will change again?
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3 years ago
A flat sheet of paper of area 0.365 m2 is oriented so that the normal to the sheet is at an angle of 60 ∘ to a uniform electric
andriy [413]

Answer:

A.) 3.65 N*m²/C B) No C) 0º D) 90º

Explanation:

A) The electric flux, when the electric field is uniform across a gausssian surface, can be calculated as the dot product of the electric field vector, and the vector representing the area of the surface (normal to the surface and directed outward it by convention), as follows:

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where E = 20 N/C, A = 0.365 m², φ = 60º.

Replacing by the values, we can get the value of the electric flux, as follows:

Flux = 20 N/C* 0.365 m²*0.5 = 3.65 N*m²/C

B) While the area remains constant, and doesn't change orientation, the value of the flux will be the same, regardless the shape of the sheet.

C) When the normal to the sheet and the electric field are parallel each other, the surface will intercept the maximum number of field lines, i.e. the flux will be directly E*A*cos 0º = E*A (maximum value possible).

D) When the electric field is tangent to the surface, this means that no field lines will be intercepted by the sheet, so the flux is zero.

In this case, φ = 90º, cos φ = 0

⇒ E*A*cos 90º = E*A*0 = 0

5 0
3 years ago
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