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Vlad1618 [11]
3 years ago
14

determine whether the following equations are dimensionally correct if not how can you make them dimensionally correct 1 /2 mv2

=(mgh) 2​
Physics
1 answer:
serg [7]3 years ago
6 0

Answer:

1 /2 mv^{2} =mgh

Explanation:

The correct equation follows the law of conservation of energy where kinetic energy is all transformed to potential energy, since we know that kinetic energy is expressed as

1 /2 mv^{2} while potential energy is mgh where m is the mass of the object, v is the velocity or speed of the object, g is acceleration due to gravity and h is the vertical height. Therefore, relating the two equations we should have 1 /2 mv^{2} =mgh

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Read 2 more answers
A tennis ball is thrown from a 25 m tall building with a zero initial velocity. At the same moment, another ball is thrown from
Nataly [62]

Answer:

The two balls meet in 1.47 sec.

Explanation:

Given that,

Height = 25 m

Initial velocity of ball= 0

Initial velocity of another ball = 17 m/s

We need to calculate the ball

Using equation of motion

s=ut+\dfrac{1}{2}gt^2+h

Where, u = initial velocity

h = height

g = acceleration due to gravity

Put the value in the equation

For first ball

s_{1}=0-\dfrac{1}{2}gt^2+25....(I)

For second ball

s_{2}=17t-\dfrac{1}{2}gt^2+0....(II)

From equation (I) and (II)

-\dfrac{1}{2}gt^2+25=17t-\dfrac{1}{2}gt^2+0

t=\dfrac{25}{17}

t=1.47\ sec

Hence, The two balls meet in 1.47 sec.

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3 years ago
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