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Vaselesa [24]
3 years ago
14

How is grounding a positive object different from grounding a negative object?

Physics
1 answer:
Natali5045456 [20]3 years ago
8 0

Answer:

Grounding a Positively Charged Object

Electrons were transferred from the electroscope to the ground. As in the case of grounding a negatively charged electroscope, the grounding of a positively charged electroscope involves charge sharing. The excess positive charge is shared between the electroscope and the ground.

Explanation:

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Se coloca una tuerca con una llave, como muestra la figura, si el brazo r= 30 cm y el torque de apriete recomendado para la fuer
irina [24]

Answer:

F = 100 N

Explanation:

The torque is given by the expression

      τ = F x r

where bold letters indicate vectors, the magnitude of this expression is

     τ = F r sin θ

In general, when tightening a nut, the force is applied perpendicular to the arm, therefore  θ = 90 and sin 90 = 1

      τ = F r

      F = τ / r

calculate

      F = 30 / 0.30

      F = 100 N

6 0
3 years ago
Your mother asks you to carry a load of wood to the fireplace and lower it to the hearth. In doing this you have used your arms
Evgesh-ka [11]

Answer: The correct answer is the weight of the wood.

Explanation:

Hope this helps

8 0
3 years ago
Read 2 more answers
What is the density of a 2 gallon milk jug that has a mass of 2.0 kg? Answer should be in g/ml.
kirill [66]

volume of milk is given as

V = 2 Gallon

we will convert it into mL unit

V = 2 Gal = 7570.82 ml

mass of the milk m = 2kg

m = 2000 g

now for the density we can use

\rho = \frac{m}{V}

\rho = \frac{2000}{7570.82}

\rho = 0.264 g/mL

<em>so the density is 0.264 g/mL for above sample</em>

8 0
4 years ago
An object is allowed to fall freely near the surface of a planet. The object has an acceleration due to gravity of 24 m/s2. How
Alborosie

Answer:

12 m

Explanation:

The object is in uniformly accelerated motion, so the distance covered can be found using the following suvat equation:

s=ut+\frac{1}{2}at^2

where

s is the distance

u is the initial velocity

t is the time

a is the acceleration

For this problem,

g=24 m/s^2

and

u = 0, since we are considering the first second of motion

So, substituting t = 1 s, we find

s=0+\frac{1}{2}(24)(1)^2=12 m

6 0
4 years ago
Conversion of one form of energy into another form is ​
Artist 52 [7]

Answer: energy transformation

5 0
2 years ago
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