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3 years ago

How is grounding a positive object different from grounding a negative object?

Physics

1 answer:

Natali5045456 [20]3 years ago

8 0

Answer:

Grounding a Positively Charged Object

Electrons were transferred from the electroscope to the ground. As in the case of grounding a negatively charged electroscope, the grounding of a positively charged electroscope involves charge sharing. The excess positive charge is shared between the electroscope and the ground.

Explanation:

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A person running down the hallway at a velocity of 4.2 m/s comes to a stop in a time of 1.8 seconds to avoid hitting the wall. W

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3 years ago

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Ronch [10]

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3 years ago

Stella has poured 3 cups of water into a 1-L soda bottle. Stella then sealed the bottle and placed it in the sunlight. What natu

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3 years ago

Como anticipan la caída del proyectil, con movimiento parabólico para que el misil no haga daño

Elena L [17]

Answer:

Conociendo la velocidad inicial del proyectil y el angulo de lanzamiento con respecto ala horizontal.

Explanation:

Para poder anticipar la caída del proyectil es importante conocer la velocidad inicial del proyectil y el angulo de disparo del proyectil con respecto a la horizontal.

A continuación se presenta un diagrama o esquema donde se pueden ver estas variables y se explicaran a la brevedad:

Para poder encontrar el rango que es la máxima distancia horizontal recorrida por el proyectil debemos utilizar la siguiente ecuación:

$x=(v_{o})_{x} *t\\where:\\(v_{o})_{x} = velocidad inicial x-component [m/s]\\t= time [s]$

Para poder encontrar el tiempo debemos utilizar la siguiente ecuación:

$y=(v_{y} )_{o}*t-0.5*g*t^{2} \\donde:\\(v_{y} )_{o}= velocidad inicial componente y [m/s]\\g = gravity = 9.81 [m/s^2]\\t = time [s]$

En la anterior ecuación, igualamos y = 0, ya que cuando el proyectil cae al suelo la distancia vertical es cero. De esta manera podemos encontrar el tiempo t, ya que conocemos la velocidad inicial del proyectil en la componente y.

Seguidamente reemplazamos t en la primera ecuacion y encontramos la distancia x o el rango.

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3 years ago

Tim jogs a distance of 7.2 km to the west. Then he turns south and jogs 1.4 km. West is the resultant if Tim's jog back to the b

vesna_86 [32]

Answer:

Explanation:

If Tim jogs a distance of 7.2 km to the west and then he turns south and jogs 1.4 km, the resultant displacement of Tim is calculated using the pythagoras theorem as shown;

R² = 7.2²+1.4²

R² = 51.84+1.96

R² = 53.8

R = √53.8

R = 7.33 km

Hence the resultant of Tim's jog back to the beginning is 7.33km

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4 years ago