<span>The answer is 62 u. The molecular mass of a molecule (Mr) is the sum of atomic masses (Ar) of its elements. Ar(Na) = 23 u. Ar(O) = 16 u. Therefore, the molecular mass of sodium oxide is 62 u: Mr(Na2O) = 2 * Ar(Na) + Ar(O) = 2 * 23 u + 16 u = 46 + 16 = 62 u.</span>
Answer:
m = 1.45 kg
Explanation:
For this exercise we look for size reduction in height
Reduction = y / y₀
Reduction = 2.15 / 6.75
Reduction = 0.3185
As the statue should not be deformed, all reduction has the same factor.
Let's use the concept of density
ρ = m / V
Initial statue
ρ = m₀ / V₀
It is reduced
V = x y z
V = 0.3185 x₀ 0.3185 y₀ 0.3185 z₀
V = 0.3185³ V₀
Density is
ρ = m / V
ρ = m / 0.3185³ V₀
As the density remains constant we can match them
m₀ / Vo = m / 0.3185³ V₀
m = 0.3185³ m₀
Let's calculate
m = 0.3185³ 45
m = 0.03231 45
m = 1.45 kg
Explanation:
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