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kobusy [5.1K]
3 years ago
9

Help me is a critic acid a solid or a liquid??​

Chemistry
1 answer:
Musya8 [376]3 years ago
7 0

Answer:

See below

Explanation:

It is neither, at least not at room temperature.

Citric acid exists as a power at room temperature, but can be crystallized from cold water. This can be considered it's " solid state, " but as I mentioned before this acid is a powder. Take a look at the attachment below. This is a citric acid present as a crystal;

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Stacy runs a paper chromatography experiment using the same ink, but two different solvents.
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Answer:

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Explanation:

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3 years ago
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How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O? The reaction is:
Readme [11.4K]

Answer:

There is 5.72 grams of H2 formed

1)  C+ H2O → CO + H2

2) We start with 34 grams of carbon that will react with an excess of H2O

3) 5.72 grams of H2

Explanation:

Step 1: Data given

Mass of carbon = 34.00 grams

H2O is in excess

Molar mass of C = 12 g/mol

Molar mass of H2O = 18.02 g/mol

Step 2: The balanced equation

C+ H2O → CO + H2

Step 3: What is the starting substance

We start with 34 grams of carbon that will react with an excess of H2O

Step 4: Calculate moles carbon

Moles C = mass C / molar mass C

Moles C = 34.00 grams / 12.00 g/mol

Moles C = 2.833 moles

Step 5: Calculate moles H2

Carbon is the limiting reactant.

For 1 mol Carbon we need 1 mol H20 to produce 1 mol CO and 1 mol H2

For 2.833 moles C we'll have 2.833 moles H2

Step 6: Calculate mass of H2

Mass H2 = moles H2 * molar mass H2

Mass H2 = 2.833 moles * 2.02 g/mol

Mass H2 = 5.72 grams of H2

8 0
4 years ago
2 questions. will give brainliest if i can figure out how
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1= b. electrons are lost

2= a. after one substance is oxidized

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Be sure to explain each step in the energy flow, identifying the form of energy represented and how it changes from one form to
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The question that you asked has already been answered

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3 years ago
Use bond energies to calculate δhrxn for the reaction. n2(g)+3cl2(g)→2ncl3(g)
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ΔHrxn = ΣδΗ(bond breaking) - ΣδΗ(bond making)

Bond enthalpies,
N ≡ N ⇒ 945 kJ mol⁻¹
N - Cl ⇒ 192 kJ mol⁻¹
Cl - Cl⇒ 242 kJ mol⁻¹

According to the balanced equation,
ΣδΗ(bond breaking)  = N ≡ N x 1 + Cl - Cl x 3
                                  = 945 + 3(242)
                                  = 1671 kJ mol⁻¹
ΣδΗ(bond making)    = N - Cl x 3 x 2
                                 = 192 x 6
                                 = 1152 kJ mol⁻¹

δHrxn = ΣδΗ(bond breaking) - ΣδΗ(bond making)
          = 1671 kJ mol⁻¹ - 1152 kJ mol⁻¹
          = 519 kJ mol⁻¹
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4 years ago
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