Answer:
The concentration of the original solution was 0.400 M
Explanation:
Step 1: Data given
Volume of the aqueous ethanol solution = 400 mL = 0.400 L
The solution was diluted to 4.00 L
The concentration of the diluted solution is 0.0400 M
Step 2: Calculate the concentration of the original solution
We use the dilution equation:
C1V1 = C2V2
⇒with C1 = the concentration of the initial solution = TO BE DETERMINED
⇒with V1 = the volume of the initial solution= 0.400 L
⇒with C2 = the concentration of the final solution= 0.0400 M
⇒with V2 = the volume of the final solution= 4.00 L
C1* 0.400 L = 0.0400 M * 4.00 L
C1 = (0.0400 M * 4.00L) / 0.400 L
C1 = 0.400 M
The concentration of the original solution was 0.400 M