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stealth61 [152]
4 years ago
12

Which one of the following processes does NOT use Calcium?

Chemistry
1 answer:
steposvetlana [31]4 years ago
3 0
The answer sould be Component of Thyroxine, Thyroxine contains iodine and are formed from thyronines, which are composed of two molecules of the amino acid tyrosine. Thyroxine contains four iodine atoms, and triiodothyronine contains three iodine atoms.
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What do elements in thr first two columns of the periodic table have in common?
maxonik [38]

The initial two columns of the periodic table make the s-square, and the components in this square share practically speaking that they have a tendency to lose electrons to pick up soundness.

7 0
3 years ago
Read 2 more answers
The diameter of neutral atoms generally decreases going left to right across one period on the periodic table. What change cause
Lubov Fominskaja [6]

Explanation:

Atomic size gradually decreases from left to right across the periodic table because within a period of elements, all electrons are added to the same shell. However, at the same time, protons are being added to the nucleus, making it more positively charged. The effect of increasing proton number is greater than that of the increasing electron number. Therefore, there is a stronger nuclear attraction. This means that the nucleus attracts the electrons more strongly, pulling the atom's electron shells closer to the nucleus. As a result, the atomic diameter of the atom decreases.

8 0
3 years ago
Does anyone have the answers to this worksheet?
abruzzese [7]
Use your periodic table
8 0
3 years ago
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What is an atomic weight?
S_A_V [24]
The average weight of an atom of an element, formerly based on the weight of one hydrogen atom taken as a unit or on 1/16 (0.0625) the weight of an oxygen atom, but after 1961 based on 1/12 the weight of the carbon-12 atom.
3 0
3 years ago
Calculate the de Broglie wavelength of a shotgun
snow_lady [41]

Answer : The de Broglie wavelength will be 3.68\times 10^{-33}m

Solution :

The formula used for de Broglie wavelength is:

\lambda=\frac{h}{mv} ..........(1)

where,

\lambda = wavelength  = ?

h = Planck's constant  = 6.626\times 10^{-34}Js

m = mass  = 1.2 g = 0.0012 kg

Conversion used : 1 kg = 1000 g

v = velocity  = 150 m/s

Now put all the given values in equation 1, we get:

\lambda=\frac{6.626\times 10^{-34}Js}{(0.0012kg)\times (150m/s)}

\lambda=3.68\times 10^{-33}m

Therefore, the de Broglie wavelength will be 3.68\times 10^{-33}m

3 0
3 years ago
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