Answer:
19.8m/s
Explanation:
Given parameters:
Mass of the ball = 10kg
Height of the rail = 20m
Unknown:
Velocity at the bottom of the rail = ?
Solution:
The velocity at the bottom of the rail is its final velocity.
Using the appropriate motion equation, we can find this parameter;
V² = U² + 2gH
V is the final velocity
U is the initial velocity
g is the acceleration due to gravity
H is the height
the ball was rolled from rest, U = 0
V² = O² + 2 x 9.8 x 20
V = 19.8m/s
Answer:
Explanation:
FROGS BREATHE THROUGH SKIN IN WATER AND THROUGH LUNGS ON LAND.
I HOPE IT WILL HELP YOU.
Hope this will help you and please mark as brainlist answer
Given- m= 1.75 g
Now moles of O2 gas= Mass/ Molar mass
n = 1.75/32
V= 2L
P= 1atm
R=0.0821.....Constant
As PV=nRT
=> T=PV/nR
= 1* 2/ (1.75/32)*0.0821 K
= 2*32/1.75* 0.0821 K
= 445.45 K
= (445.45- 273.15) degrees celsius
= 172.30 degrees celsius..... ANSWER
