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3 years ago

Which substance in cigarettes numbs the throat to allow for deeper inhalation?

Chemistry

1 answer:

aleksandr82 [10.1K]3 years ago

8 0

b. menthol
Menthol is also used in cough drops to provide a cooling sensation

You might be interested in

How many molecules are in 2.50 moles of O2

amm1812

There are 6.022×1023 O2 molecules in a mole of O2. Since you have 2 oxygen atoms in one O2 molecule, there are 2×6.022×1023 O atoms in a mole of O2.

7 0

3 years ago

Consider the following mechanism for the reaction between nitric oxide and ozone:

swat32

Answer:

A . 2 O₃(g) + 2 NO ⇒ 2 O₂ (g) + 2 NO₂(g)

B . Yes

C. O and NO₃

Explanation:

A. The overall reaction is obtained by adding the individual steps in the reaction mechanism where we will get the reactants and product and the intermediates will cancel.

Thus, adding 1+ 2 +3 we get

2 O₃(g) + 2 NO ⇒ 2 O₂ (g) + 2 NO₂(g)

B. The reaction intermediates are those that are produced from the initial and/or subsequent steps and are consumed later on in the reaction mechanism, but are neither reactants nor products, they just participate.

From this definition it follows that O(g) and NO₃ are reaction intermediates.

C. O and NO₃

6 0

4 years ago

Write the name for: Mg3O2

sveticcg [70]

Answer:

you sure it is the right sign your using

4 0

2 years ago

A solution of sodium hydroxide is standardized against potassium hydrogen phthalate (KHP, formula weight 204.2 g/mol). From the

enyata [817]

<u>Answer:</u> The molarity of NaOH solution is 0.273 M.

<u>Explanation:</u>

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of KHP = 1.794 g

Molar mass of KHP = 204.2 g/mol

Putting values in above equation, we get:

$\text{Moles of KHP}=\frac{1.794g}{204.2g/mol}=0.0088mol$

The chemical reaction for the reaction of KHP and NaOH follows

$KHC_8H_4O_4(aq.)+NaOH\rightarrow KNaC_8H_4O_4(aq.)+H_2O(l)$

By Stoichiometry of the reaction:

1 mole of KHP reacts with 1 mole of NaOH.

So, 0.0088 moles of KHP will react with = $\frac{1}{1}\times 0.0088=0.0088mol$ of NaOH

To calculate the molarity of NaOH, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

We are given:

Moles of NaOH = 0.0088 moles

Volume of solution = [32.47 - 0.23] mL = 32.24 mL = 0.03224 L (Conversion factor: 1 L = 1000 mL)

Putting values in above equation, we get:

$\text{Molarity of NaOH }=\frac{0.0088mol}{0.03224L}=0.273M$

Hence, the molarity of NaOH solution is 0.273 M.

3 0

3 years ago

A sample of fluorine gas has a volume of 5.63 L at 14°C and standard pressure. What will be the pressure in atm if the moles of

soldier1979 [14.2K]

With standard pressure there is a set list of values. (at STP), most common is 760torr. So whenever you see "at STP" or "at standard temperature pressure" you will use 760torr for pressure. Same thing goes with temperature, if you're not given temp and it says at STP you will use 273K.

For this problem:

You will be using the combined gas law:

(Pressure 1) x (Volume 1) / (Temp. 1) = (Pressure 2) x (Volume 2) / (Temp. 2)

(760torr) x (5.63L) / (287K) = (?) (9.21L) / (287K)

Pressure 2 = 465torr

*Hope this clarifies STP for you! :)

6 0

4 years ago