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amm1812
3 years ago
8

Density and Years: What do you know?Objectives: determine and compare density of pennies to assess composition. Procedure:1. Rea

d the directions and create a data table accordingly.2. Place 15-20 pennies in order of consecutive dates. Find the mass of each penny and record.3. Find the volume of all 5 pennies by water displacement and record in your data table. Record the volume adding 5 more pennies at a time until you have measured them all (15-20).a. Find the average volume of 1 penny.4. Calculate the density of each penny and graph according to the year.5. If the density of copper is 8.96 g/cm3 what would the mass of a pure copper penny be?6. Draw a conclusion.7. How might this relate to a real world example?
Chemistry
1 answer:
fgiga [73]3 years ago
5 0

Answer:I dunno

Explanation:it is the best thing I ever said in this app

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A sodium ion, Na+, with a charge of 1.6×10−19C and a chloride ion, Cl− , with charge of −1.6×10−19C, are separated by a distance
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Answer:

W\geq 2.1x10^{-19}J

Explanation:

Due to Coulomb´s law electric force can be described by the formula F=K\frac{q_{1}.q_{2}}{r^{2}}, where K is the Coulomb´s constant (9x10^{9} N\frac{m^{2} }{C^{2} }), q_{1}= Charge 1 (Na+ in this case), q_{2} is the charge 2 (Cl-) and r is the distance between both charges.

Work made by a force is W=F.d and total work produced is the change in energy between final and initial state. this is W=W_{f} -W_{i}.

so we have W=W_{f} -W_{i} =(K\frac{q_{(Na+)}q_{(Cl-)}rf}{r_{f} ^{2}})-(K\frac{q_{(Na+)}q_{(Cl-)}ri}{r_{i} ^{2}})=Kq_{(Na+)}q_{(Cl-)[\frac{1}{{r_{f}}} -\frac{1}{{r_{i}}}]

Given that ri= 1.1nm= 1.1x10^{-9}m and rf= infinite distance

W=(9x10^{9})(1.6x10^{-19})(-1.6x10^{-19})[\frac{1}{\alpha }-\frac{1}{(1.1x10^{-9})}]=2.1x10^{-19}J

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