The formula for pH is -log [H+] where [H+] is the Molarity. Therefore if you plug the numbers in your answer will be 2.77
A "A wind factor"
since an abiotic is a non-living condition or thing, The wind would be the most logical answer.
Hope this helped :D
hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.
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When presented with balanced chemical equation, the same phase can be cancelled out only when they appear to be in the opposite side of the equation. This means that in one equation, a certain chemical is a product. However, on the next equation, that same substance can be the reactant.
Moles of Na theoretically extract : 10.256
<h3>Further explanation</h3>
Given
600 g of NaCl
Required
moles of Na
Solution
Na can be electrolyzed from NaCl(molten)
Na⁺ + e⁻⇒ Na
Cl⁻⇒1/2 Cl₂ + e⁻
Overall reaction :
NaCl⇒Na + 1/2 Cl₂ x2
<em>2NaCl⇒2Na + Cl₂</em>
mol of NaCl(MW=58.5 g/mol) :
= 600 g : 58.5 g/mol
= 10.256
From the equation, mol ratio of NaCl : Na = 2 : 1, so :
mol Na = mol NaCl = 10.256