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FinnZ [79.3K]
3 years ago
10

I need to graph 6x-2y=-14 and covert it’s into slope intercept form

Mathematics
1 answer:
Verizon [17]3 years ago
8 0

Answer:

Standard form you can leave it as y=-6x-14

________ or. y=3x+7

-2

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Prove: The sum of two multiples of 3 is a multiple of 3
andrey2020 [161]

Answer:

  3 . . . goes in both boxes

Step-by-step explanation:

Use the distributive property. Remove the common factor to outside parentheses:

  3(m +n) = a multiple of 3

6 0
2 years ago
Can someone help me with this question? Thank you!
Harrizon [31]

\qquad\qquad\huge\underline{{\sf Answer}}

Let's evaluate ~

The given expression is :

\qquad \sf  \dashrightarrow \:4x + 8

plug the value of x as 3

\qquad \sf  \dashrightarrow \:4(3) + 8

\qquad \sf  \dashrightarrow \:12 + 8

\qquad \sf  \dashrightarrow \:20

Therefore, the required value is 20

8 0
2 years ago
Please help me i need help bad
Elena L [17]

Answer:

Line segment A' B' has a length of 2 units, and line segment C' D' has a length of 4 units.

Step-by-step explanation:

All we need to do is count the units in between the line segments.

3 0
2 years ago
Give the correct name for<br> 2x3 + 5x
NikAS [45]

Answer: x(2x²+5)

please give brainliest if it helped

8 0
3 years ago
which of the following expresses the coordinates of the foci of the conic section shown below? (x-2)^2/4+(y+5)^2/9
elena55 [62]

Step-by-step explanation:

\frac{(x - 2) {}^{2} }{4}  +  \frac{(y + 5) {}^{2} }{9}  = 1

This is the equation of the ellipse. Since the denominator is greater for the y values, we have a vertical ellipse. Remember a>b, so a

The formula for the foci of the vertical ellipse is

(h,k+c) and (h,k-c).

where c is

Our center (h,k) is (2, -5)

{c}^{2}  =  {a}^{2}  -  {b}^{2}

Here a^2 is 9, b^2 is 4.

{c}^{2}  = 9 - 4

{c}^{2}  = 5

c =  \sqrt{5}

So our foci is

(2, - 5 +  \sqrt{5} )

and

(2, - 5 -  \sqrt{5} )

6 0
1 year ago
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