Is this a function ?|x|

Which system has no solution y=-3x+8 6x+2y=-4.5

Galina-37 [17]

I think it’s y=3x+8 I’m not sure if that’s what you’re asking me

6 0

3 years ago

When does a compound inequality with OR have a solution that is the entire number line? Can the solution be bounded to one side?

dalvyx [7]

Answer:

Concept: Algebraic Analysis

$\geqslant \: \: \: \: \: \: \: \: \: \: \leqslant$
Those two symbols indicate one solution
$< \: \: \: \: \: \: \: >$
Those symbols indicate a range of values
$x < 15 < x$
Indicates two bounded answers
In an inequality there is always a solution

6 0

3 years ago

Help with Geometry Homework Please?

Harrizon [31]

The answer for the first slot is Alternate Interior Angles Theorem
Angle B and angle G are inside the "train tracks" formed by AB and GH. They are on opposite sides of the transversal line BG.

Along a similar line of reasoning, the answer for the second slot is Alternate Exterior Angles Theorem
The two parallel lines in question are AC and FH. The transversal line is FC. Angles ACB and HFG are on the exterior of the "train tracks" formed by the parallel lines.

3 0

3 years ago

The given line segment has a midpoint at (3, 1).

Katena32 [7]

Answer:

$y=\frac{1}{3}x$

Step-by-step explanation:

The given line segment has a midpoint at (3, 1) and goes through (2, 4), (3, 1), and (4, -2). We can use any two of the three points to calculate the equation of the line. Let us use the points (2, 4) and (4, -2)

Therefore the line goes through (2, 4) and (4, -2). The equation of a line passing through $(x_1,y_1)\ and\ (x_2,y_2)$ is:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}$ .

Therefore the line passing through (2, 4) and (4, -2) has an equation:

$\frac{y-y_1}{x-x_1}=\frac{y_2-y_1}{x_2-x_1}\\\frac{y-4}{x-2}=\frac{-2-4}{4-2}\\\frac{y-4}{x-2}=\frac{-6}{2}\\y-4=x-2(-3)\\y-4=-3x+6\\y=-3x+10$

Comparing with the general equation of line: y = mx + c, the slope (m) = -3 and the intercept on the y axis (c) = 10

Two lines are said to be perpendicular if the product of their slope is -1. If the slope of line one is m1 and the slope of line 2 = m2, then the two lines are perpendicular if:

$m_1m_2=-1$ .

Therefore The slope (m2) of the perpendicular bisector of y = -3x + 10 is:

$m_1m_2=-1\\-3m_2=-1\\m_2=\frac{1}{3}$

Since it is the perpendicular bisector of the given line segment, it passes through the midpoint (3, 1). The equation of the perpendicular bisector is:

$\frac{y-y_1}{x-x_1}=m\\\frac{y-1}{x-3}=\frac{1}{3}\\ y-1= \frac{1}{3}(x-3)\\ y-1=\frac{1}{3}x-1\\y=\frac{1}{3}x$

the equation, in slope-intercept form, of the perpendicular bisector of the given line segment is $y=\frac{1}{3}x$

7 0

3 years ago

Read 2 more answers

denny can deliver 6 papers every 15 minutes and brendan can deliver 5 papers in that same amount of time. how many papers can th

Evgesh-ka [11]

So for this problem you know that 15 is 1/4 of an hour so to get the amount of papers each individual could deliver by themselves in an hour you would multiply the amount they can deliver in 15 minutes by 4. Denny delivers 6 so multiplying that by 4 is 24. Next Brendan delivers 5 in 15 minutes so multiplying that by 4 you get 20. The final step is to add 20 and 24 to get the total amount of papers between the two of them that gets delivered in an hour. This will result in your answer of 44.

7 0

4 years ago

Read 2 more answers

Is this a function ?|x| - y = 2