The mass percentage would be reduced but not as much as if it were a complete reaction ヽ༼ຈل͜ຈ༽ﾉ︵┻━┻ mark brainliest please
42- 8 = 34 sand dunes must be the answer
hope so it helps
Answer:
100ml of a stock 50% KNO3 solutions are needed to prepare 250ml of a 20% KNO3 solution.
Explanation:
In the given question it is mentioned that
S1=50%
V2=250ml
S2= 20%
We all know that
V1S1=V2S2
∴V1= V2×S2÷S1
∴V1= V2S2×1/S1
∴V1= 250×20÷50
∴V1= 100ml
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Answer:
it is iodine it seems very right
