The pressure exerted by each individual gas in a mixture of gases is called its <u>partial </u>pressure this pressure is proportional to the <u>mole</u> fraction of the gas in the mixture
Pressure is defined as the force of all the gas particle of wall collisions divided by the area of the wall
The pressure exerted by an individual gas in a mixture is known as its partial pressure and assuming we have a mixture of ideal gases and we can use the ideal gas law to solve problems involving gases in a mixture and the ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components
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Answer:
The answer to your question is 33.4 ml
Explanation:
Data
volume 1 = V1 = 42 ml
temperature 1 = T1 = 20°C
temperature 2 = T2 = -60°C
Volume 2 = V2 = x
Process
1.- Convert celsius to kelvin
T1 = 20 + 273 = 293°K
T2 = -60 + 273 = 233°K
2.- Use the Charles' law to solve this problem
Solve for V2
V2 = 
3.- Substitution
V2 = 
4.- Simplification
V2 = 
5.- Result
V2 = 33.4ml
It should be 3.36 g / min but i m not sure
Hellium argon neon xenon krypton randon oxygen fluorine chlorine bromine
First, we have to see how K2O behaves when it is dissolved in water:
K2O + H20 = 2 KOH
According to reaction K2O has base properties, so it forms a hydroxide in water.
For the reaction next relation follows:
c(KOH) : c(K2O) = 1 : 2
So,
c(KOH)= 2 x c(K2O)= 2 x 0.005 = 0.01 M = c(OH⁻)
Now we can calculate pH:
pOH= -log c(OH⁻) = -log 0.01 = 2
pH= 14-2 = 12
