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snow_tiger [21]
4 years ago
5

Two objects attract each other gravitationally. If the mass of each object doubles, how does the gravitational force between the

m change?
Physics
1 answer:
madam [21]4 years ago
6 0

Answer:

The gravitational force between them quadruples

Explanation:

According to law of gravitation, the force of attraction (F) between two masses m1 and m2 is directly proportional to the product of the masses and inversely proportional to the square of the distance(r) between them. Mathematically,

F1 = Gm1m2/r²... 1

If their masses doubles, the formula becomes;

F2 = G(2m1)(2m2)/r²

F2 = 4Gm1m2/r² ... 2

Dividing equation 2 by 1, we have;

F2/F1 = {4Gm1m2/r²}÷{Gm1m2/r²}

F2/F1 = 4Gm1m2/r²×r²/Gm1m2

F2/F1 = 4

F2 = 4F1

The gravitational force between the masses when they doubles quadruples.

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4 years ago
An egg is Free Falling Down from a nest in a tree (neglect air resistance)​
DedPeter [7]

We are to calculate the acceleration.

Answer:

-9.8 m/s²

Explanation:

Since the egg is in a free fall, it means that the force due to gravity will be equal to the normal force.

Now,

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-g = a

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3 years ago
Air friction damps a tuning fork so the amplitude decreases by 1/10 per second. Resonances] 10 Hz. what % chnge in frequency res
aleksandr82 [10.1K]

Answer:

The percentage change in frequency is 10%.

Explanation:

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Amplitude decreases by 1/10 per second.

Resonance = 10 Hz

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Using formula of change in frequency

\Delta f=\Delta A\times R

Put the value into the formula

\Delta f=\dfrac{1}{10}\times10

\Delta f=1\ Hz

We need to calculate the resonant frequency

Using formula of resonant frequency

f_{r}=R-\Delta f

Put the value into the formula

f_{r}=10-1

f_{r}=9\ Hz

We need to calculate the percentage change in frequency

Using formula of percentage change in frequency

f=\dfrac{10-9}{10}

f=10\%

Hence, The percentage change in frequency is 10%.

7 0
4 years ago
In a football game, a 96 kg receiver leaps straight up in the air to catch the 0.42 kg ball the quarterback threw to him at a vi
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Answer:

V = 0.074 m/s

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given,

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mass of the ball, m = 0.42 Kg

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initial speed of the receiver = 0 m/s

final speed.V = ?

using conservation of momentum

M u + m v = (M + m) V

0 + 0.42 x 17 = (96+0.42) V

96.42 V = 7.14

V = 0.074 m/s

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4 years ago
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Answer:

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