Answer:
Due to equal pressure in all the direction at a particular level in a fluid medium (Pascal's Law)
Explanation:
We are not crushed by the weight of the atmosphere because atmosphere is a fluid and we are immersed into it. So, according to the Pascal's law the the pressure a each point in a horizontal level is equal in all the direction irrespective of the orientation of a body.
Variation of pressure in term of the height of a fluid medium is given as:
![P=\rho.g.h](https://tex.z-dn.net/?f=P%3D%5Crho.g.h)
density of fluid
g = acceleration due to gravity
h = height of the free surface of the fluid from the immersed object.
- And atmosphere has very less variation of pressure with change in height as it is a rare medium fluid and so for a human height there is very negligible variation of pressure at the heat of a human with respect to his toe.
Answer:
5.15348 Beats/s
4.55 mm
Explanation:
= Velocity of sound = 342 m/s
= Velocity of sound = 346 m/s
= First frequency = 440 Hz
Frequency is given by
![f_2=\frac{v_2}{2L_1}\\\Rightarrow f_2=\frac{346}{2\times 0.38863}\\\Rightarrow f_2=445.15348\ Hz](https://tex.z-dn.net/?f=f_2%3D%5Cfrac%7Bv_2%7D%7B2L_1%7D%5C%5C%5CRightarrow%20f_2%3D%5Cfrac%7B346%7D%7B2%5Ctimes%200.38863%7D%5C%5C%5CRightarrow%20f_2%3D445.15348%5C%20Hz)
Beat frequency is given by
![|f_1-f_2|=|440-445.15348|=5.15348\ Beats/s](https://tex.z-dn.net/?f=%7Cf_1-f_2%7C%3D%7C440-445.15348%7C%3D5.15348%5C%20Beats%2Fs)
Beat frequency is 5.15348 Hz
Wavelength is given by
![\lambda_1=\frac{v_1}{f}\\\Rightarrow \lambda_1=\frac{342}{440}\\\Rightarrow \lambda_1=0.77727\ m](https://tex.z-dn.net/?f=%5Clambda_1%3D%5Cfrac%7Bv_1%7D%7Bf%7D%5C%5C%5CRightarrow%20%5Clambda_1%3D%5Cfrac%7B342%7D%7B440%7D%5C%5C%5CRightarrow%20%5Clambda_1%3D0.77727%5C%20m)
Relation between length of the flute and wavelength is
![\lambda_1=2L_1\\\Rightarrow L_1=\frac{\lambda_1}{2}\\\Rightarrow L_1=\frac{0.77727}{2}\\\Rightarrow L_1=0.38863\ m](https://tex.z-dn.net/?f=%5Clambda_1%3D2L_1%5C%5C%5CRightarrow%20L_1%3D%5Cfrac%7B%5Clambda_1%7D%7B2%7D%5C%5C%5CRightarrow%20L_1%3D%5Cfrac%7B0.77727%7D%7B2%7D%5C%5C%5CRightarrow%20L_1%3D0.38863%5C%20m)
At v = 346 m/s
![\lambda_2=\frac{v_2}{f}\\\Rightarrow \lambda_2=\frac{346}{440}\\\Rightarrow \lambda_1=0.78636\ m](https://tex.z-dn.net/?f=%5Clambda_2%3D%5Cfrac%7Bv_2%7D%7Bf%7D%5C%5C%5CRightarrow%20%5Clambda_2%3D%5Cfrac%7B346%7D%7B440%7D%5C%5C%5CRightarrow%20%5Clambda_1%3D0.78636%5C%20m)
![L_2=\frac{\lambda_2}{2}\\\Rightarrow L_2=\frac{0.78636}{2}\\\Rightarrow L_2=0.39318\ m](https://tex.z-dn.net/?f=L_2%3D%5Cfrac%7B%5Clambda_2%7D%7B2%7D%5C%5C%5CRightarrow%20L_2%3D%5Cfrac%7B0.78636%7D%7B2%7D%5C%5C%5CRightarrow%20L_2%3D0.39318%5C%20m)
Difference in length is
![\Delta L=L_2-L_1\\\Rightarrow \Delta L=0.39318-0.38863\\\Rightarrow \Delta L=0.00455\ m=4.55\ mm](https://tex.z-dn.net/?f=%5CDelta%20L%3DL_2-L_1%5C%5C%5CRightarrow%20%5CDelta%20L%3D0.39318-0.38863%5C%5C%5CRightarrow%20%5CDelta%20L%3D0.00455%5C%20m%3D4.55%5C%20mm)
It extends to 4.55 mm
Force = mass × accelaration
Force = 0.25Kg × 196 m/s²
Force = 49 Newtons
When the force of air resistance on the skydiver
is equal to the skydiver's weight.
Answer:
B. 30 m down
Explanation:
In physics we have two types of quantities:
- Scalar quantity: it is a quantity which only has a magnitude (e.g: mass and time are scalar quantities, since they only have a magnitude)
- Vector quantity: it is a quantity which has both a magnitude and a direction (e.g: velocity is a vector quantity, since it has a magnitude (the speed) and a direction)
In this problem, we have:
A. 100 ounces of water --> scalar (this is a volume, which has only a magnitude)
B. 30 m down --> vector (this is a displacement, which has both a magnitude (30 m) and a direction (down)
C. 88 mi/s --> scalar (this is a speed, which has only a magnitude)
D. 45 gallons in a bucket --> scalar (this is a volume, which has only a magnitude)
So, the correct option is B.