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3 years ago

If a pendulum has a period of 2.4 seconds what is the frequency?

1 answer:

4 0

We can use the equation $Peroid = \frac{1}{Frequency}$ to calculate the frequency.
Rearranging this gives us $Frequency = \frac{1}{Period}$ .
So the frequency is $\frac{1}{2.4}$ , which equals 0.42 hertz
(to 2 decimal places).

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If you could help me please.

11Alexandr11 [23.1K]

1) Does a 1 kg object weight 9.8 newtons on the moon? why?

No. 1kg of mass does not weigh 9.8N on the moon.

Weight = (mass) x (gravity).

Gravity is 9.8 m/s² on Earth, but gravity is only 1.62 m/s² on the moon.

2) How much does a 3-kg object weigh (on earth) in newtons?

Weight = (mass) x (gravity)

Gravity = 9.8 m/s² on Earth.

Weight = (3 kg) x (9.8 m/s² )

Weight = 29.4 N

3) How much does a 20-kg object weigh (on earth) in newton?

Weight = (mass) x (gravity)

Gravity = 9.8 m/s² on Earth.

Weight = (20 kg) x (9.8 m/s² )

Weight = 196 N

4) What must happen for the mass of an object to change?

When an object moves, its mass increases. The faster it moves, the greater its mass gets. But this is all part of Einstein's "Relativity". The object has to move at a significant fraction of the speed of light before any change can be noticed or measured. So as far as we are concerned, in everyday life, the mass of an object doesn't change, no matter where it is, or what you do to it.

5) What are 2 ways the weight of an object can change?

First, remember that the mass of an object doesn't change, no matter where it is, what you do to it, or what else is around it.

But its weight can change, because its weight depends on the strength of gravity in the place where the object is, and that gravity is the result of what else is around it in the neighborhood. So the weight can change even though the mass doesn't.

The weight of an object changes if you take it to a place where gravity is stronger or weaker.

Let's say we have an object whose mass is 90.72 kilograms. Like me !

As long as I stay on earth, where gravity is 9.8 m/s² , I weigh 889 Newtons (200 pounds).

. . . Fly me to the moon. Gravity = 1.62 m/s² Weight = 147 Newtons (33 lbs)

. . . Drag me to Jupiter. Gravity = 24.8 m/s² Weight = 2,249 N (506 pounds)

My mass never changed, but my weight sure did.

8 0

3 years ago

Describe how velocity and speed are different

Vaselesa [24]

Answer: Velocity involves a particular direction, i.e. North. Speed does not include a direction.

6 0

3 years ago

Read 2 more answers

Conduction of a nerve impulse would be the fastest in _________

Vinil7 [7]

The options of the given are:

A. A large diameter myelinated fiber

B. A small diameter myelinated fiber

C. A large unmyelinated fiber

D. A small unmyelinated fiber

E. A small fiber with multiple Schwann cells

Answer: Option A, A large diameter myelinated fiber.

Explanation:

The conduction of the nerve impulse would be greatest in the myelinated fiber because the main function of the myelin sheath is to increase the speed of the impulse at which the electrical signals propagate.

In case of the unmyelinated sheath the nerve impulse travels slowly as the conduction waves but in case of the large diameter myelinated sheath the signals travel via saltatory conduction( hop)

In this type of propagation the signals are transferred from the node of Ranvier in one neuron to next node which increases the overall velocity of the action potentials.

8 0

3 years ago

7. A stick of length L and mass M is hanging at rest from its top edge from a ceiling hinged at that point so that it is free to

Lilit [14]

Answer:

The distance from the top of the stick would be 2l/3

Explanation:

Let the impulse 'FΔt' acts as a distance 'x' from the hinge 'H'. Assume no impulsive reaction is generated at 'H'. Let the angular velocity of the rod about 'H' just after the applied impulse be 'W'. Also consider that the center of percussion is the point on a bean attached to a pivot where a perpendicular impact will produce no reactive shock at the pivot.

Applying impulse momentum theorem for linear momentum.

FΔt = m(Wl/2), since velocity of center of mass of rod = Wl/2

Similarly applying impulse momentum theorem per angular momentum about H

FΔt * x = I * W

Where FΔt * x represents the impulsive torque and I is the moment of inertia

F Δt.x = (ml² . W)/3

Substituting FΔt

M(Wl/2) * x = (ml². W)/3

1/x = 3/2l

x = 2l/3

8 0

3 years ago

At what distance above the surface of the earth is the gravitational field 4.9 m/s^2

san4es73 [151]

That's 1/2 of what it is on the surface.

The distance between the center of the Earth and any object
on the surface is 1 Earth radius ... about 3960 miles.

Gravitational force is inversely proportional to the square of
the distance between the centers of the objects, so in order
to reduce the acceleration of gravity by 1/2, you increase the
distance by √2 .

   (3960 miles) x (√2) = 5,600 miles from the center

   = 1,640 miles above the surface.

5 0

4 years ago