My name is lilliannnnnnnn
As we know that as per Newton's II law we have
here we will have
= change in momentum
= time interval in which momentum is changed
now in order to have least injury during jumping we need to have least force on the jumper
so in order to have least force we can say that the momentum must have to change in maximum time so that amount of force must be least
So we need to increase the time in which momentum of the system is changed
The sum of more than one velocity vector.
Or the sum of an initial velocity vector and an acceleration vector integrated over time.
Answer:
E = 2.17 x 10⁻² V/m
Explanation:
First we will find out the current density by using the formula:
J = I/A
where.
J = Current Density = ?
I = Current = 5.5 A
A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²
Therefore,
J = 5.5 A/7.068 x 10⁻⁶ m²
J = 0.778 x 10⁶ A/m²
Now, we calculate the magnitude of applied field:
E = ρJ
where,
E = Magnitude of applied field = ?
ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m
Therefore,
E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)
<u>E = 2.17 x 10⁻² V/m</u>