Question

The amplitudes of the displacement and acceleration of an unbalanced motor were measured to be 0.15 mm and 0.6 g, respectively. Determine the speed of the motor . Use g=9.81 m/s^2 .

Answer 1

Answer:

N=945.76 RPM

Explanation:

Given that

A= 0.15 m

Acceleration = 0.6 g

a=0.6 x 9.81 m/s²

a= 5.886 m/s²

We know that acceleration a given as

a = ω² A

ω=Angular speed

$\omega=\sqrt{\dfrac{0.6\times 9.81}{0.6\times 10^{-3}}}$

 ω=99.04 rad/s

We know that

$\omega=\dfrac{2\pi N}{60}\\\\N=\dfrac{60\times \omega}{2\pi }$

$N=\dfrac{60\times 99.04}{2\pi }$

N=945.76 RPM

Therefore the speed of the motor will be 945.76 RPM.