Answer:
2.41 g of NaCl is needed
Explanation:
Molarity of solution = (Number of moles of solute)/(Volume of solution in Litre)
Here sodium chloride (NaCl) is solute in saline solution
275 mL = 0.275 L
So, number of moles of NaCl in 275 mL saline solution =
Molar mass of NaCl = 58.44 g/mol
Number of moles = (mass)/(molar mass)
So, mass of 0.04125 moles of NaCl =
So, 2.41 g of NaCl is needed
I believe it is current. An ammeter is a measuring instrument used to measure the current in a circuit. Electric currents are measured in amperes (A), hence the name. Instruments used to measure smaller currents, milliampere or microampere range, are designated as milliammeters or microammeters.
Volume of H2 produced = 57.6576 L
<h3>Further explanation</h3>
Given
23.17 g Be
Required
Volume of H2
Solution
Reaction
Be(s)+H2O(g)→BeO(s)+H2(g)
mol Be :
= 23.17 g : 9 g/mol
= 2.574
From the equation, mol H2 : mol Be = 1 : 1, so mol H2 = 2.574
Volume H2(assumed at STP, 1 mol=22.4 L) :
= 2.574 x 22.4 L
= 57.6576 L