A,B,C or D which of the following can be concluded regarding the movement represented in the graph?
1 answer:
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Refer to the diagram shown below.
The hoist is in static equilibrium supported by tensions in the two ropes.
For horizontal force balance, obtain
T₃ cos 50 = T₂ cos 38
0.6428T₃ = 0.788T₂
T₃ = 1.2259T₂ (1)
For vertical force balance, obtain
T₂ sin 38 + T₃ sin 50 = 350
0.6157T₂ + 0.766T₃ = 350 (2)
Substitute (1) into (2).
0.6157T₂ + 0.766(1.2259T₂) = 350
1.5547T₂ = 350
T₂ = 225.124 N
T₃ = 1.2259(225.124) = 275.979
Answer:
T₂ = 225.12 N
T₃ = 275.98 N
The hoist is in static equilibrium supported by tensions in the two ropes.
For horizontal force balance, obtain
T₃ cos 50 = T₂ cos 38
0.6428T₃ = 0.788T₂
T₃ = 1.2259T₂ (1)
For vertical force balance, obtain
T₂ sin 38 + T₃ sin 50 = 350
0.6157T₂ + 0.766T₃ = 350 (2)
Substitute (1) into (2).
0.6157T₂ + 0.766(1.2259T₂) = 350
1.5547T₂ = 350
T₂ = 225.124 N
T₃ = 1.2259(225.124) = 275.979
Answer:
T₂ = 225.12 N
T₃ = 275.98 N
Answer: Tension = 47.8N, Δx = 11.5× m.
Tension = 95.6N, Δx = 15.4× m
Explanation: A speed of wave on a string under a tension force can be calculated as:
is tension force (N)
μ is linear density (kg/m)
Determining velocity:
0.0935 m/s
The displacement a pulse traveled in 1.23ms:
Δx = 11.5×
With tension of 47.8N, a pulse will travel Δx = 11.5× m.
Doubling Tension:
|v| = 0.1252 m/s
Displacement for same time:
15.4×
With doubled tension, it travels 15.4×
m