Compared to a cold object, a hotter object of the same size emits most of its light at __________ wavelengths and emits _____ li
1 answer:
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Answer:
a. 2.0secs
b. 20.4m
c. 4.0secs
d. 141.2m
e. 40m/s, ∅= -30°
Explanation:
The following Data are giving
Initial speed U=40m/s
angle of elevation,∅=30°
a. the expression for the time to attain the maximum height is expressed as
where g is the acceleration due to gravity, and the value is 9.81m/s if we substitute values we arrive at
b. the expression for the maximum height is expressed as
c. The time to hit the ground is the total time of flight which is twice the time to reach the maximum height ,
Hence T=2t
T=2*2.0
T=4.0secs
d. The range of the projectile is expressed as
e. The landing speed is the same as the initial projected speed but in opposite direction
Hence the landing speed is 40m/s at angle of -30°