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ozzi
4 years ago
9

A particle is moving with a constant speed of 25 m/s in 90 m radius circle what is the angular speed in radian per second about

the center of a circle
Physics
1 answer:
valentina_108 [34]4 years ago
6 0

Answer:

the angular speed in radian per second about the center of a circle is 0.278 rad/s

Explanation:

Given;

Linear velocity v = 25m/s

Radius of circular path r = 90m

The linear velocity of the particle can be expressed as a function of the angular speed as;

Linear velocity = angular speed × radius of path

v = wr

w = v/r

Where;

v = linear velocity

r = radius

w = angular speed

Substituting the given values, we have;

w = 25/90 = 0.278 rad/s

the angular speed in radian per second about the center of a circle is 0.278 rad/s

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Gold has a specific heat of 0.130 J/g*C. If 195 joules of heat are added to 15 grams of gold how much does the temperature of th
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The correct answer to the question is :  100\ ^0C

EXPLANATION :

As per the question, the specific heat of gold is given as c = 0.130\ J/g^0C

The heat given to the gold dQ = 195 J

The mass of the gold is given as m = 15 gram.

We are asked to calculate the change in temperature.

Let the change in temperature is dT.

We know that dQ = mcdT

                      dT=\ \frac{dQ}{mc}

                             =\ \frac{195}{15\times 0.130}

                             =\ 100\ ^0C                   [ANS]

Hence, the change in temperature is 100 degree celsius.

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4 years ago
A 12.0 V battery delivers a 0.40 A current to an electric motor that is connected across the battery terminals. What power is co
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Answer:

4.8 watts

Explanation:

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2 years ago
Which organ allows the exchange of oxygen and carbon dioxide?​
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Respiratory System

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3 years ago
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Where does the body get each of these
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Glucose - from the food we eat, then the food is broken down into another type of sugar called glucose.

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On a hot summer day in the state of Washington while kayaking, I saw several swimmers jump from a railroad bridge into the Snoho
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Answer: part a: 19.62m

part b: 19.62 m/s

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u=0

a=9.81 m/s2

t=2 secs

s=ut+0.5at^2

s=h

h=0*2+0.5*9.81*2^2\\h=19.62 meters

Part b

v=u+at\\v=0+9.81*2\\v=19.62m/s

Part c

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