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3 years ago

From inside to out, describe the components of an atom. What makes one element's atoms differ from another element's atoms?

1 answer:

4 0

From the outside is it’s shell, and on the inside is the nucleus (on the middle) which is made or protons (positive charge) and neutrons (neutral charge which is negate and positive) and Lastly there are electrons (negative charge) that orbit the nucleus like planets orbiting the Sun. The shell gets made as the electrons orbit the nucleus.
How do atoms differ from eachother?- their atoms might have different elections, neutrons, and/ or protons inside of it. Plus the location of the elections might be different too.

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2 Pont

Reptile [31]

Answer:

A. It makes astronauts weightless.

Explanation:

Gravity does not make astronauts feel weightless. Astronauts are weightless because they are orbiting at the same rate as their shuttle.

Although the force of gravity weakens as one moves away from the earth surface, it does not mean that this force is absent in orbit

Gravitational force has a constant acceleration value near the earth surface which is commonly known to be 9.8m/s².
It is a force of attraction tending to hold and bind bodies together so far they have mass.
This force keeps every thing from escaping space-ward from the earth surface.

6 0

2 years ago

In physics the use of force to move an object is called work. True or false?

KatRina [158]

True

hope this helps!

8 0

3 years ago

A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the

lisabon 2012 [21]

Magnitude of acceleration = (change in speed) / (time for the change) .

Change in speed = (ending speed) - (starting speed)

= zero    - (43 m/s)

=    -43 m/s .

Magnitude of acceleration = (-43 m/sec) / (0.28 sec)

      = (-43 / 0.28) (m/sec) / sec

      =    153.57... m/s²

      = 1.5... x 10² m/s² .

5 0

3 years ago

Read 2 more answers

Researchers at the University of Georgia have evaluated trends in streamside forests in areas within roughly 400 feet of the sta

Colt1911 [192]

B: adds aesthetic value to the landscape. Think about it, out of all your options, that's the one that doesn't really help anything.

And I took the test, so take my word for it.

6 0

2 years ago

What is the orbital period of a spacecraft in a low orbit near the surface of mars? The radius of mars is 3.4×106m.

valkas [14]

<h2>Answer: 56.718 min</h2>

Explanation:

According to the Third Kepler’s Law of Planetary motion “The square of the orbital period of a planet is proportional to the cube of the semi-major axis (size) of its orbit”.

In other words, this law states a relation between the orbital period $T$ of a body (moon, planet, satellite) orbiting a greater body in space with the size $a$ of its orbit.

This Law is originally expressed as follows:

$T^{2}=\frac{4\pi^{2}}{GM}a^{3}$ (1)

Where;

$G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

$M=6.39(10)^{23}kg$ is the mass of Mars

$a=3.4(10)^{6}m$ is the semimajor axis of the orbit the spacecraft describes around Mars (assuming it is a circular orbit and a low orbit near the surface as well, the semimajor axis is equal to the radius of the orbit)

If we want to find the period, we have to express equation (1) as written below and substitute all the values:

$T=\sqrt{\frac{4\pi^{2}}{GM}a^{3}}$ (2)

$T=\sqrt{\frac{4\pi^{2}}{(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(6.39(10)^{23}kg)}(3.4(10)^{6}m)^{3}}$ (3)

$T=\sqrt{11581157.44 s^{2}}$ (4)

Finally:

$T=3403.1099s=56.718min$ This is the orbital period of a spacecraft in a low orbit near the surface of mars

6 0

3 years ago