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3 years ago

8

A dust particle floats in front of a silent loudspeaker as shown in the figure. The loudspeaker is turned on and plays a constan

t low frequency note.

2 answers:

dybincka [34]3 years ago

8 0

Answer:tbh idk

Explanation:

tbh idk

notka56 [123]3 years ago

4 0

Explanation:

question not clear. please upload full equation

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If a rocket travels 35,200 miles in 2 hours, what is its speed?

Brrunno [24]

Answer:

Given:

Distance = 35200 miles, time = 2 hr.

So we know = 35200/ 2, = 17600 miles / hr.

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3 years ago

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Polar molecules have ionic bonds.<br> True<br> False

Nadusha1986 [10]

Polar molecules do have ionic bonds

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3 years ago

What is needed to create a magnetic field?

lara [203]

Explanation:

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3 years ago

A yellow train of mass 100 kg is moving at 8 m/s toward an orange train of mass 200 kg traveling in the opposite direction on th

Serhud [2]

The initial momentum of the yellow and the orange train is 1000kgm/s.

Momentum is the product of the mass and velocity of any object.

Momentum is denoted by P.

Momentum P = mv , where m = mass and v = velocity.

<h3>Given:</h3>

Mass of the orange train = 200kg

Velocity of the orange train = 1m/s

So, the momentum of the orange train will be,

∴ P = mv

P = 200 x 1

P = 200 kgm/s

∴ The initial momentum of the orange train is 200kgm/s.

Mass of the yellow train = 100kg

Velocity of the yellow train = 8m/s

So, the momentum of the yellow train will be,

∴ P = mv

P = 100 x 8

P = 800 kgm/s

∴ The initial momentum of the yellow train is 800kgm/s.

Therefore, the initial momentum of the yellow and the orange train is 1000kgm/s.

Learn more about momentum here:

brainly.com/question/25849204

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5 0

2 years ago

A stone is thrown horizontally with an initial speed of 10 m/s from the edge of a cliff. A stopwatch measures the stone's trajec

olga2289 [7]

Answer:

The height of the cliff is 90.60 meters.

Explanation:

It is given that,

Initial horizontal speed of the stone, u = 10 m/s

Initial vertical speed of the stone, u' = 0 (as there is no motion in vertical direction)

The time taken by the stone from the top of the cliff to the bottom to be 4.3 s, t = 4.3 s

Let h is the height of the cliff. Using the second equation of motion in vertical direction to find it. It is given by :

$h=u't+\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}gt^2$

$h=\dfrac{1}{2}\times 9.8\times (4.3)^2$

h = 90.60 meters

So, the height of the cliff is 90.60 meters. Hence, this is the required solution.

5 0

3 years ago