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sdas [7]
3 years ago
8

A car accelerates at a constant rate from 12 m/s to 27 m/s while it travels 125 m. How long does it take to achieve this speed?

Physics
1 answer:
MArishka [77]3 years ago
3 0

Answer:

6.41 s

Explanation:

Under constant acceleration we know that

average velocity × time taken = displacement

s=\frac{u+v}{2}t

125=\frac{27+12}{2}t

    t = 6.41 s

The proof of used equation is given in the attachment.

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A car moves with a speed of 72 km/h for 15 minutes and then with a speed of 80 km/h for the next 12 minutes. The total distance
sukhopar [10]

Answer:

The total distance covered by the car is 3,810.08 m

Explanation:

Given;

initial speed of the car, u = 72 km/hr = 20 m/s

initial time, t₁ = 15 minutes = 900 s

final speed of the car, v = 80 km/hr = 22.22 m/s

final time, t₂ = 12 minutes = 720 s

The acceleration of the car is given as;

a = \frac{v-u}{t_2 -t_1} \\\\a = \frac{22.22-20}{900-720}\\\\a = 0.0123 \ m/s^2

The total distance covered by the car is given as;

v² = u² + 2as

where;

s is the total distance covered by the car

22.22² = 20² + 2(0.0123)s

22.22²  - 20² = 2(0.0123)s

93.728 = 0.0246s

s = 93.728 / 0.0246

s = 3,810.08 m

Therefore, the total distance covered by the car is 3,810.08 m

8 0
3 years ago
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You are an industrial engineer with a shipping company. As part of the package- handling system, a small box with mass 1.60 kg i
Kisachek [45]

Answer:

v = 0.84m/s, v(max)= 0.997m/s

Explanation:

Initial work done by the spring, where c is the compression = 0.28m:

W_s = \frac{1}{2}kc^2

Work lost to friction:

W_f =\mu mg(c-x)

Energy:

E = W_s-W_f=\frac{1}{2}kc^2 -\mu mg(c-x)=\frac{1}{2}mv^2+\frac{1}{2}kx^2

(a) Solve for v:

v=\sqrt{\frac{k}{m}(c^2-x^2)-2\mu g(c-x)}

(b) Solve \frac{dv}{dx}=0 for x:

\frac{dv}{dx}=\frac{\mu g-\frac{k}{m}x}{\sqrt{\frac{k}{m}(c^2-x^2)-2\mu g(c-x)}}

\frac{dv}{dx}=0 if:

\mu g-\frac{k}{m}x = 0

x_{max} = \frac{\mu gm}{k}

v_{max}=\sqrt{\frac{k}{m}c^2-2\mu gc+(\mu g)^2\frac{m}{k}}

6 0
3 years ago
A car is traveling at 16 m/s^2
Leya [2.2K]
Really? wow that's pretty cool
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How much work is done by a forklift raising a 125 kg object a distance of 10 meters?
lozanna [386]

W = Fd

W = 1225 N x 10 m = 12250

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3 years ago
Please help me it is for learning at home.
Temka [501]

Answer:

What do you need help with?

Explanation:

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