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sdas [7]
4 years ago
8

A car accelerates at a constant rate from 12 m/s to 27 m/s while it travels 125 m. How long does it take to achieve this speed?

Physics
1 answer:
MArishka [77]4 years ago
3 0

Answer:

6.41 s

Explanation:

Under constant acceleration we know that

average velocity × time taken = displacement

s=\frac{u+v}{2}t

125=\frac{27+12}{2}t

    t = 6.41 s

The proof of used equation is given in the attachment.

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A worker pushes a box across the floor to the right at a constant speed with a force of 25N. What
icang [17]

Answer:

Friction between the box and the floor is 25N to the left

Explanation:

There are two forces acting on the box along the horizontal direction:

- The force of push applied by the worker, in the forward direction, F

- The force of friction, F_f, acting in the opposite direction (backward)

So the net force acting on the box is

F_{net}=F-F_f

According to Newton's second law of motion, the net force on an object is equal to the product between its mass (m) and its acceleration (a), so we can write:

F_{net}=ma

And so

F-F_f = ma

However, in this case the box is moving at constant speed; this means that its acceleration is zero:

a=0

Therefore we have:

F-F_f=0

Which means

F_f=F

And since we are told that

F=25 N

This means that the force of friction is also 25 N:

F_f=F=25 N

6 0
4 years ago
Read 2 more answers
Of the solar radiation entering the atmosphere, about ___% reaches the surface directly as direct radiation.
strojnjashka [21]
Of the solar radiation entering the atmosphere, about 22.5% reaches the surface directly as direct radiation and is being absorbed. Thirty five percent of it is reflected back to the space. While 10.5% and 14.5% are scattered to the earth from the blue sky and from clouds, respectively. Also, 17.5 percent was being absorbed by the atmosphere. Thus leaving only 22.5% to be given directly to the Earth's surface. Also, another factor of this low value would be the transparency of the atmosphere. The atmosphere of the Earth has only an effective transparent to radiation from the sun of about .34 to .7 micrometer. 
8 0
3 years ago
The height of a wave crest is called __________________________. a energy b rest position c amplitude d freqency e wavelength
Sladkaya [172]
B. rest position
  hope this helps!!!
7 0
3 years ago
A .005kg projectile leaves a 1500kg launcher with a velocity of 750 m/s. What is the recoil velocity of the projectile
docker41 [41]

Answer:

The recoil velocity of the projectile is 0.0025m/s

Explanation:

Given:

Mass of the projectile =0.005kg

Mass of the launcher = 1500kg

Velocity =  750 m/s.

To Find:

The recoil velocity of the projectile = ?

Solution:

The recoil velocity is the obtained by dividing the "recoil momentum"  by the "mass of the recoil body".  The recoil momentum is equal to the momentum of the other body. The momentum of the other body is equal to it mass times its velocity.

Lets find the recoil momentum,

Recoil momentum = mass of the projectile X velocity

Recoil momentum =0.005 \times 750

Recoil momentum = 3.75

Now Recoil Velocity,

Recoil Velocity = \frac{\text { Recoil Momentum}}{\text {Mass of the launcher}}

Recoil Velocity = \frac{ 3.75}{1500}

Recoil Velocity = 0.0025m/s

7 0
4 years ago
The magnet below is cut in half. what will be the result?
loris [4]

Answer:

the correct would be c

Explanation:

a magnet will always have a north and a south so if you cut the magnet in half the north part would have a south on the opposite end and vice versa .

3 0
3 years ago
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