A reaction starts with 20.0 g of lithium hydroxide (LiOH) and actually produces 31.0 g of lithium chloride (LiCl), what is the p ercent yield? (Hint: First calculate the theoretical yield of lithium chloride (LiCl))
64.5%
88.6%
81.5%
92.8%
2 answers:
Answer:
88.6%
Explanation:
Hello,
In this case, considering the given reaction, we notice a 1:1 molar relationship between lithium hydroxide (molar mass=23.95 g/mol) and lithium chloride (molar mass=42.394 g/mol), for that reason, we are able to compute the theoretical yield of lithium chloride by stoichiometry:
Next, by knowing the actual yield of 31.0 g, we compute the percent yield as:
Therefore, among the given, the answer should be 88.6%
Best regards.
Answer:
87.6 %
Explanation:
Step 1: Write the balanced equation
LiOH + KCl ⇒ LiCl + KOH
Step 2: Calculate the theoretical yield of LiCl
We will use the following relations:
The molar mass of LiOH is 23.95 g/mol. The molar ratio of LiOH to LiCl is 1:1. The molar mass of LiCl is 42.39 g/mol.
The theoretical yield of LiCl from 20.0 g of LiOH is:
Step 3: Calculate the percent yield of LiCl.
We will use the following expression.
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