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3 years ago

PLEASE HELP!!!!! (20 points!)

Physics

2 answers:

lisov135 [29]3 years ago

6 0

Answer:

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Explanation:

1. Nebular cloud of gas and dust.

2. Cloud collapses under the force of its own gravitational attraction; usually triggered by a supernova.

3. Condensed material begins to combine and form a core center. As it warms, a protostar is formed.

4. Other gas and matter of the nebular cloud begin to rotate around the protostar, forming a flattened, disk.

5. Stellar core heats as it grows; nuclear fusion begins and a star is born.

6. Nuclear energy runs out; death; possible supernova.

Stellar evolution explains the lifecycle of a star. How it is born out of a nebula which is a cloud of dust and gases. This cloud collapses under its own gravity to make smaller molecular clouds and releases gravitational potential energy. These smaller clouds then condenses into a sphere of hot gases known as protostar. These protostars will continue to grow by accretion of dust and gases from molecular cloud and form pre main sequence star. The mass of star at this stage decides whether the Star will be a brown dwarf, white dwarf, or blue giant.

valentina_108 [34]3 years ago

3 0

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thank me later

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Which is most likely a covalent compound?<br><br> LiF<br> MgS<br> NH3<br> CaCl2

Artemon [7]

Answer:

NH₃

Explanation:

The compound that is covalent from the given choices is NH₃.

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This bond type involves the sharing of electrons between two atoms with similar electronegativities.
Nitrogen and hydrogen forms stable configuration that are isoelectronic with noble gases by sharing their valence electrons.
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2 years ago

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A circular coil that has =130 turns and a radius of =11.5 cm lies in a magnetic field that has a magnitude of 0=0.0725 T directe

Levart [38]

I think is the half of 130

7 0

3 years ago

J.J. Thomson discovered the electron by noticing that: A. molecules with the same atoms exhibited the same chemical properties.

GenaCL600 [577]

J.J. Thomson discovered the electron by noticing that a beam of particles could be influenced by an electric or magnetic force.. That is option B.

<h3>What is an electron?</h3>

An electron can be defined as the part of an atom that is negatively charged and is found revolving round the nucleus of an atom.

J.J. Thomson was the scientist that discovered electrons through subjecting two oppositely-charged electric plates around the cathode ray.

He noticed that the particles where deflected by both the magnetic and electric fields.

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4 0

2 years ago

A 10-kg package drops from chute into a 25-kg cart with a velocity of 3 m/s. The cart is initially at rest and can roll freely w

amid [387]

Answer:

(a) the final velocity of the cart is 0.857 m/s

(b) the impulse experienced by the package is 21.43 kg.m/s

Explanation:

Given;

mass of the package, m₁ = 10 kg

mass of the cart, m₂ = 25 kg

initial velocity of the package, u₁ = 3 m/s

initial velocity of the cart, u₂ = 0

let the final velocity of the cart = v

(a) Apply the principle of conservation of linear momentum to determine common final velocity for ineleastic collision;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

10 x 3 + 25 x 0 = v(10 + 25)

30 = 35v

v = 30 / 35

v = 0.857 m/s

(b) the impulse experienced by the package;

The impulse = change in momentum of the package

J = ΔP = m₁v - m₁u₁

J = m₁(v - u₁)

J = 10(0.857 - 3)

J = -21.43 kg.m/s

the magnitude of the impulse experienced by the package = 21.43 kg.m/s

(c)

the initial kinetic energy of the package is calculated as;

$K.E_i = \frac{1}{2} mu_1^2\\\\K.E_i = \frac{1}{2} \times 10 \times (3)^2\\\\K.E_i = 45 \ J\\\\$

the final kinetic energy of the package;

$K.E_f = \frac{1}{2} (m_1 + m_2)v^2\\\\K.E_f = \frac{1}{2} \times (10 + 25) \times 0.857^2\\\\K.E_f = 12.85 \ J$

the fraction of the initial energy lost;

$= \frac{\Delta K.E}{K.E_i} = \frac{45 -12.85}{45} = 0.71$

7 0

3 years ago

Describe Kinetic Energy.

mina [271]

In physics, the kinetic energy of an object is the energy that it possesses due to its motion. It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity. Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes. The same amount of work is done by the body when decelerating from its current speed to a state of rest.

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3 years ago