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creativ13 [48]
3 years ago
9

PLEASE HELP!!!!! (20 points!)

Physics
2 answers:
lisov135 [29]3 years ago
6 0

Answer:

Step 2

Step 4

Step 6

Step 5

Step 1

Step 3

Explanation:

1. Nebular cloud of gas and dust.

2. Cloud collapses under the force of its own gravitational attraction; usually triggered by a supernova.

3. Condensed material begins to combine and form a core center. As it warms, a protostar is formed.

4. Other gas and matter of the nebular cloud begin to rotate around the protostar, forming a flattened, disk.

5. Stellar core heats as it grows; nuclear fusion begins and a star is born.

6. Nuclear energy runs out; death; possible supernova.

Stellar evolution explains the lifecycle of a star. How it is born out of a nebula which is a cloud of dust and gases. This cloud collapses under its own gravity to make smaller molecular clouds and releases gravitational potential energy. These smaller clouds then condenses into a sphere of hot gases known as protostar. These protostars will continue to grow by accretion of dust and gases from molecular cloud and form pre main sequence star. The mass of star at this stage decides whether the Star will be a brown dwarf, white dwarf, or blue giant.

valentina_108 [34]3 years ago
3 0
Step 2
step 5
step 4
step 6
step 1
step 3

thank me later
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5 0
1 year ago
A+10 u charge and a -10 4C (1 HC - 106 C), at a distance of 0.3 m,
Marina CMI [18]

Answer:

B. Attract each other with a force of 10 newtons.

Explanation:

Statement is incorrectly written. <em>The correct form is: A </em>+10\,\mu C<em> charge and a </em>-10\,\mu C<em> at a distance of 0.3 meters. </em>

The two particles have charges opposite to each other, so they attract each other due to electrostatic force, described by Coulomb's Law, whose formula is described below:

F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}} (1)

Where:

F - Electrostatic force, in newtons.

\kappa - Electrostatic constant, in newton-square meters per square coulomb.

|q_{A}|,|q_{B}| - Magnitudes of electric charges, in coulombs.

r - Distance between charges, in meters.

If we know that \kappa  = 8.988\times 10^{9}\,\frac{N\cdot m^{2}}{C^{2}}, |q_{A}| = |q_{B}| = 10\times 10^{-6}\,C and r = 0.3\,m, then the magnitude of the electrostatic force is:

F = \frac{\kappa \cdot |q_{A}|\cdot |q_{B}|}{r^{2}}

F = 9.987\,N

In consequence, correct answer is B.

4 0
3 years ago
If BHALA AHMAD KHAN applied the 20N force is applied on an object moving with the velocity 30 m/s. calculate the power in KW.
Leokris [45]

Answer:0.6kw

Explanation:

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Power=20×30=600w

In kw it's going to be 600/1000=0.6kw

4 0
3 years ago
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