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3 years ago

Need help on all three pizza?

Physics

1 answer:

ahrayia [7]3 years ago

7 0

1. 12m/s and here’s how. The equation for calculating velocity of a wave is lambda x frequency. So 2m x 6Hz. Hz can be 1/s so the only unit of measurement we get is meters and seconds. So the answer will be 12m/s.

2. Frequency=2Hz period= 0.5 seconds
Equation for frequency is velocity/wavelength. 10m/s divides by 5m = 2Hz.
Equation for period is 1 / frequency. 1 divided by 2 = 0.5 seconds

3. The answer is the picture of you can’t read my hand writing comment and say “ I need the info about the wave because I can’t read your hand writing “ thank you and I hoped I helped

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A 0.14-MIN baseball is dropped from rest. It has a momentum of 0.90 kg⋅m/skg⋅m/s just before it lands on the ground.

nikitadnepr [17]

The time spent in the air by the ball at the given momentum is 6.43 s.

The given parameters;

<em>momentum of the ball, P = 0.9 kgm/s</em>
<em>weight of the ball, W = 0.14 N</em>

The impulse experienced by the ball is calculated as follows;

$Ft = \Delta P$

where;

$Ft$ is impulse

$\Delta P$ is change in momentum

The time of motion of the ball is calculated as follows;

$t = \frac{\Delta P}{F} \\\\t = \frac{0.9 - 0}{0.14} \\\\t = 6.43 \ s$

Thus, the time spent in the air by the ball at the given momentum is 6.43 s.

Learn more here:brainly.com/question/13468390

7 0

2 years ago

A spherical capacitor contains a charge of 3.00 nC when connected to a potential difference of 230 V. If its plates are separate

Assoli18 [71]

Answer:

Part(a): the capacitance is 0.013 nF.

Part(b): the radius of the inner sphere is 3.1 cm.

Part(c): the electric field just outside the surface of inner sphere is $\bf{2.81 \times 10^{4}~n~C^{-1}}$ .

Explanation:

We know that if 'a' and 'b' are the inner and outer radii of the shell respectively, 'Q' is the total charge contains by the capacitor subjected to a potential difference of 'V' and ' $\epsilon_{0}$ ' be the permittivity of free space, then the capacitance (C) of the spherical shell can be written as

$C = \dfrac{4 \pi \epsilon_{0}}{(\dfrac{1}{a} - \dfrac{1}{b})}~~~~~~~~~~~~~~~~~~~~~~~~~~~(1)$

Part(a):

Given, charge contained by the capacitor Q = 3.00 nC and potential to which it is subjected to is V = 230V.

So the capacitance (C) of the shell is

$C &=& \dfrac{Q}{V} = \dfrac{3 \times 10^{-90}~C}{230~V} = 1.3 \times 10^{-11}~F = 0.013~nF$

Part(b):

Given the inner radius of the outer shell b = 4.3 cm = 0.043 m. Therefore, from equation (1), rearranging the terms,

$&& \dfrac{1}{a} = \dfrac{1}{b} + \dfrac{1}{C/4 \pi \epsilon_{0}} = \dfrac{1}{0.043} + \dfrac{1}{1.3 \times 10^{-11} \times 9 \times 10^{9}} = 31.79\\&or,& a = \dfrac{1}{31.79}~m = 0.031~m = 3.1~cm$

Part(c):

If we apply Gauss' law of electrostatics, then

$&& E~4 \pi a^{2} = \dfrac{Q}{\epsilon_{0}}\\&or,& E = \dfrac{Q}{4 \pi \epsilon_{0}a^{2}}\\&or,& E = \dfrac{3 \times 10^{-9} \times 9 \times 10^{9}}{0.031^{2}}~N~C^{-1}\\&or,& E = 2.81 \times 10^{4}~N~C^{-1}$

3 0

3 years ago

Define speed and what is it’s SI unit.

Nadusha1986 [10]

Speed can be thought of as the rate at which an object covers distance. ... Speed has the dimensions of distance divided by time. The SI unit of speed is the metre per second, but the most common unit of speed in everyday usage is the kilometre per hour or, in the US and the UK, miles per hour........?

7 0

3 years ago

Read 2 more answers

The rope of a swing is 3.10 m long. Calculate the angle from the vertical at which a 76.0 kg man must begin to swing in order to

kakasveta [241]

Answer:

The angle from the vertical is 48.72°

Explanation:

Given :

Length of rope $l = 3.10$ m

Mass of man $m = 76$ Kg

Mass of car $M = 1520$ Kg

Velocity of car $v = 1.01$ $\frac{m}{s}$

According to conservation law,

Potential energy of man is converted to kinetic energy of car moving,

$\frac{1}{2} M v^{2} = mgh$

We calculate height,

$h = \frac{M v^{2} }{2mg}$

$h = \frac{1520(1.01)^{2} }{2\times 75 \times 9.8}$ ( ∵ $g = 9.8 \frac{m}{s^{2} }$ )

$h = 1.05$ m

This is the distance of the rope at the bottom,

So we take difference of it.

⇒ $3.10 - 1.05 = 2.05$

We can calculate angle between them,

$\cos \theta = \frac{2.05}{3.10} = 0.6597$

$\theta =$ 48.72°

Therefore, the angle from the vertical is 48.72°

8 0

3 years ago

A taut rope has a mass of 0.123 kg and a length of 3.54 m .What average power must be supplied to the rope to generate sinusoida

gladu [14]

Answer:

811.54 W

Explanation:

Solution

Begin with the equation of the time-averaged power of a sinusoidal wave on a string:

P = $\frac{1}{2\\}$ μ.T².ω².v

The amplitude is given, so we need to calculate the linear mass density of the rope, the angular frequency of the wave on the rope, and the frequency of the wave on the string.

We need to calculate the linear density to find the wave speed:

μ = $\frac{M}{L}$ = 0.123Kg/3.54m

The wave speed can be found using the linear mass density and the tension of the string:

v= 22.0 ms⁻¹

v = f/λ = 22.0/6.0×10⁻⁴

= 36666.67 s⁻¹

The angular frequency can be found from the frequency:

ω= 2πf=2π(36666.67s−1) = 2.30 ×10⁻⁵s⁻¹

Calculate the time-averaged power:

P = $\frac{1}{2}$ μΤ²×ω²×ν

= $\frac{1}{2}$ ×( 0.03475kg/m)×(0.0002)²×(2.30×10⁵)² × 22.0

= 811.54 W

5 0

3 years ago