Answer:
P₁ = 219.3 Pa
Explanation:
This fluid mechanics problem, we can use that the pressure is distributed with the same value throughout the system, which is Pascal's principle.
Let's use the subinidce1 for the small diameter and the subscript 2 for the larger diameter.
P₁ = P₂
pressure is defined by
P = F / A
we subtitute
F₁ / A₁ = F₂ / A₂
F₁ = F₂ A₁ / A₂
the area in a circle is
A = π r² = π d² / 4
we substitute
F₁ = F₂ (d₁ / d₂)²
we calculate
F₁ = 17640 (2/32)²
F₁ = 68.9 N
Having the force to be applied we can find the air pressure on the small plunger
P₁ = F₁ / A₁
P₁ = F₁ 4 / π d₁²
let's calculate
P₁ = 68.9 4 / (π 0.02²)
P₁ = 219.3 Pa
When light passes from a faster medium into a slower medium, light will be refracted toward a line drawn perpendicular to the point of refraction. <em>(B)</em>
When you jumó ur legs put force on ground
Answer:
Whether the force exerted by the locomotive on the wall was larger
Than the force the locomotive could exert on the wall.
Explanation:
The Newton's third law of motion States that every force have it's equal and opposite reaction force, whose magnitude is the same as the applied force. Therefore the magnitude of these opposite forces will be equal.
So we have;
F12=-F21
F12 is the force in a direction
-F21 is the force in the opposite direction.
Therefore we see that the magnitude of the force the locomotive exerts on the wall is equal to the one the wall exerts on the locomotive. Both magnitudes are equal but in opposite directions.
