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Talja [164]
4 years ago
5

Explanation of thermosphere​

Physics
1 answer:
Vikki [24]4 years ago
3 0
The region of the atmosphere above the mesosphere and below the height at which the atmosphere ceases to have the properties of a continuous medium.
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2. A test model for an experimental gasoline engine does 45 J of work in one cycle
loris [4]

Answer: im just trying to get some points so i can answer my question.

sorry

Explanation:

7 0
3 years ago
A bullet is shot from a rifle with a velocity of 720 m/s. What is the velocity of the bullet in km/h.
Elan Coil [88]

Answer:

2592 km/h

Explanation:

Given that a bullet is shot from a rifle with a velocity of 720 m/s. What is the velocity of the bullet in km/h.

The velocity = 720 m/s

Solution

To convert metres per second to kilometer per hour, you will multiply by 3600 and divide by 1000

720 × 3600/1000

720 × 3.6

72 × 36

2592 km/h

Therefore, the velocity of the bullet in kilometer per hour is 2592 km/h

8 0
3 years ago
What is the formula to calculate moisture content?
Black_prince [1.1K]

Calculation of moisture content. Calculate the moisture content on a wet-weight basis using the following formula: Moisture content (%) = W2 - W3 x 100 W2-W1. where, W1 = weight of container with lid; W2 = weight of container with lid and sample before drying; and W3 = weight of container with lid and sample after drying.

8 0
4 years ago
A certain moving electron has a kinetic energy of 0.991 × 10−19 J. Calculate the speed necessary for the electron to have this e
alisha [4.7K]

Answer: The speed necessary for the electron to have this energy is 466462 m/s

Explanation:

Kinetic energy is the energy posessed by an object by virtue of its motion.

K.E=\frac{1mv^2}{2}

K.E= kinetic energy = 0.991\times 10^{-19}J

m= mass of an electron = 9.109\times 10^{-31}kg

v= velocity of object = ?

Putting in the values in the equation:

0.991\times 10^{-19}J=\frac{1\times 9.109\times 10^{-31}kg\times v^2}{2}

v=466462m/s

The speed necessary for the electron to have this energy is 466462 m/s

4 0
3 years ago
Read 2 more answers
Nick raises a 4-kg mass vertically 0.05 meters above his head. Determine the work done on the mass.
Misha Larkins [42]

The work done by Nick as he raises the given mass over the given distance is approximately 2 Joules.

Given the data in the question:

  • Mass raised; m = 4kg
  • Distance covered; d = 0.05m

Work done; W = \ ?

First we calculate the force used to raise the mass to the given distance.

Since the movement was vertical, the force must over come the mass and the pull of gravity ( g = 9.8m/s^2 ).

Using Newton's second law of Motion;

F = m * g

We substitute our values into the equation

F = 4kg * 9.8m/s^2\\\\F = 39.2 kgm/s^2

Now, we determine the work done by Nick.

Work done is simply the energy transferred from one store to another.

It is expressed as;

Work\ done = force * distance\\\\W = F * d

So we substitute our values into the equation

W = 39.2kgm/s^2 * 0.05m\\\\W = 1.96kgm^2/s^2\\\\W = 2 J

Therefore, the work done by Nick as he raises the given mass over the given distance is approximately 2 Joules.

Learn more about Newton's law of motion: brainly.com/question/20066791

8 0
3 years ago
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