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Ksenya-84 [330]
3 years ago
15

How does the atomic arrangement of atoms lead to its crystal structure like was it was seen in the sample of bronze with gold an

d tin atoms?
Chemistry
2 answers:
marysya [2.9K]3 years ago
5 0
<span>atomic arrangement of atoms lead to its crystal structure like was it was seen in the sample of bronze with gold and tin atoms is due to their metallic bond hope it helps


</span>
Nat2105 [25]3 years ago
4 0
Crystal structure would be commonly found in solid compounds.
Atomic arrangement of atoms in this kind of structure usually very symmetrical and highly ordered. Causing the component within the structure is so strong and hard to break

hope this helps
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A solution of HNO3 has a [H+] concentration of 0.001 M. What is the pH of point
Citrus2011 [14]

Answer:

3

Explanation:

pH=-log(H+)

- Hope that helps! Please let me know if you need further explanation.

7 0
3 years ago
Two identical pots, one black and one silver, containing exactly the same amounts of water, are heated to the same temperature.
I am Lyosha [343]
The most probable answer is: (a) <span>The black pot emits heat at a faster rate than the silver pot. It means the black pot conducts heat at a higher rate than the silver pot, that's why it cooled off faster. It also means that the silver pot retains heat better and is more of an insulator.</span>
7 0
2 years ago
Read 2 more answers
An object has a density of 16.3 g/mL and a volume of 0.46 L. Calculate the
deff fn [24]

Answer:

16.53 pounds

Explanation:

this type of problem needs convertion method we need to convert from grams to pound.

3 0
2 years ago
2c4H10 +13O2 —&gt;8CO2+10H2O to find how many moles of oxygen would react with 4.3 mol C4H10
Elena-2011 [213]

Answer:

\large\boxed{\text{28 mol of O$_{2}$}}

Explanation:

             2C₄H₁₀ + 13O₂ ⟶ 8CO₂ + 10H₂O

n/mol:      4.3  

13 mol of O₂ react with 2 mol of 2C₄H₁₀

\text{Moles of O}_{2} = \text{4.3 mol C$_{4}$H$_{10}$} \times \dfrac{\text{13 mol O}_{2}}{\text{2 mol C$_{4}$H$_{10}$}} = \textbf{28 mol O}_{2}\\\\\text{The reaction requires $\large\boxed{\textbf{28 mol of O$_{2}$}}$}

5 0
2 years ago
Consider the reaction of NO and CO to form N2 and CO2, according to the balanced equation: 2 NO (g) + 2 CO (g) → N2 (g) + 2 CO2
Gekata [30.6K]

The image is not given in the question, it is attached below:

<u>Answer:</u> The excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

<u>Explanation:</u>

In the given image:

Red spheres represent oxygen atoms, blue spheres represent nitrogen atoms and black spheres represent carbon atoms

The combination of 1 black and 2 red spheres will represent carbon dioxide (CO_2) compound

The combination of 2 blue spheres will represent nitrogen molecule (N_2)

The combination of 1 blue and 1 red sphere will represent nitrogen monoxide (NO) compound

The combination of 1 black and 1 red sphere will represent nitrogen monoxide (NO) compound

Limiting reagent is defined as the reagent which is completely consumed in the reaction and limits the formation of the product.

Excess reagent is defined as the reagent which is left behind after the completion of the reaction.

We are given:

Given moles of NO = 6 moles

Given moles of CO = 4 moles

For the given chemical equation:

2NO(g)+2CO(g)\rightarrow N_2(g)+2CO_2(g)

By stoichiometry of the reaction:

If 2 moles of CO reacts with 2 moles of NO

So, 4 moles of CO will react with = \frac{2}{2}\times 4=4mol of NO

As the given amount of NO is more than the required amount. Thus, it is present in excess and is considered as an excess reagent.

Thus, CO is considered a limiting reagent because it limits the formation of the product.

Hence, the excess reactant is NO, the limiting reactant is CO and the products are shown in the image attached below.

3 0
2 years ago
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