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Goshia [24]
3 years ago
14

Please help me i can’t get this one right. someone help me please if you know how to do this.

Mathematics
1 answer:
Sati [7]3 years ago
4 0

Answer:

it’s going up by 3 boys per girl!

Step-by-step explanation:

Correct me if I’m wrong by commenting down below.

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O A PQR is reflected over the x-axis. What are the<br> coordinates of O'?
topjm [15]

Answer:

(8,-2)

Step-by-step explanation:

When reflecting something across the X axis the y axis coordinate is the one that will change to put the position further up or down.  In this case we are moving it down to the same amount below the axis that it is now above it.  That means that since it is currently 2 above the X axis it would then be 2 below the X axis making it at -2 so the coordinates would be (8,-2)

I hope this helps and please don't hesitate to ask if there is anything still unclear!

7 0
3 years ago
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Solve for x<br> x+1=−10<br> x=?<br> Tell me what x is
melisa1 [442]
<h3>♫ :::::::::::::::::::::::::::::: // Hello There ! //  :::::::::::::::::::::::::::::: ♫</h3>

➷  x + 1 = -10

- 1 from both sides to isolate x

x = -10 - 1

Solve:

x = -11

<h3><u>❄️</u></h3>

➶ Hope This Helps You!

➶ Good Luck (:

➶ Have A Great Day ^-^

↬ ʜᴀɴɴᴀʜ ♡

8 0
3 years ago
Bill draws a regular octagon. He divides the octagon into eight congruent isosceles triangles. What are the measures of the thre
elixir [45]
Is there any more info you can give?
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4 years ago
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F(x)=1/2×+6 plz helpppppppppp​
FromTheMoon [43]

Answer:

The solution set can be given as:

\{x|x\ \epsilon\ R,x\neq -3\}

Step-by-step explanation:

Given function:

f(x)=\frac{1}{2x+6}

To find the domain of the function in set notation.

Solution:

For the function f(x) to exist the denominator must be ≠ 0

We have the denominator (2x+6) which  cannot be = 0.

Thus, we can find the domain of the function using the above relation.

The function f(x) will not exist when:

2x+6=0

Solving for x

Subtracting both sides by 6.

2x+6-6=0-6

2x=-6

Dividing both sides by 2.

\frac{2x}{2}=\frac{-6}{2}

∴ x=-3

Thus, the function will not exist at x=-3. This means it has all real number solutions except -3.

The solution set can be given as:

\{x|x\ \epsilon\ R,x\neq -3\}

3 0
4 years ago
Number 19. Answer to number 19) the figure shows a game...
Artemon [7]
Where is the figure?
Can you show it?
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