What is 8/9 divided by 10/3?
2 answers:
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Answer:
The equation of line perpendicular to given line and passing through point (4 , - 6) is y = - 2 x - 2
Step-by-step explanation:
Given as :
The equation of line is
y = x - 3
Now, standard equation of line is
y = m x + c
where m is the slope of line and c is the y-intercept
So, comparing with standard line equation with given line equation
∴ slope of given line = m =
Again
other line is perpendicular to given line and passes through point (4 , - 6)
Let The slope of other line = M
∵ Two lines are perpendicular
∴ <u>From perpendicular lines property , the product of lines = - 1</u>
i.e m × M = -1
Or, × M = -1
Or M =
∴ M = - 2
So, The slope of other line = M = - 2
<u>Now, equation of line with slope - 2 and points (4 , - 6) in slope-point form</u>
y - = M (x -
)
Or, y - ( - 6) = ( -2) × (x - 4)
Or, y + 6 = - 2 x + 4
Or, y = - 2 x + 4 - 6
∴ y = - 2 x - 2
So, The equation of other line is y = - 2 x - 2
Hence, The equation of line perpendicular to given line and passing through point (4 , - 6) is y = - 2 x - 2 Answer
Answer:
(x, y) = (3, -6)
Step-by-step explanation:
I like a good graphing calculator for solving systems of equations by graphing.
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If you're solving these by hand, you need to graph the equations. It can be convenient to put the equations into "intercept form" so you can use the x- and y-intercepts to draw your graph.
That form is ...
x/(x-intercept) +y/(y-intercept) = 1
Dividing a standard-form equation by the constant on the right will put it in this form.
x/(-12/2) +y/(-12/3) = 1 . . . . . . divide the first equation by -12
x/(-6) +y/(-4) = 1 . . . . . . . . . . . the x-intercept is -6; the y-intercept is -4
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x/(12/10) +y/(12/3) = 1 . . . . . . divide the second equation by 12
x/1.2 +y/4 = 1 . . . . . . . . . . . . . the x-intercept is 1.2*; the y-intercept is 4
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The locations of these intercepts and the slopes of the lines tell you that the solution will be in the fourth quadrant. The lines intersect at (x, y) = (3, -6).
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* It can be difficult to draw an accurate graph using an intercept point that is not on a grid line. It may be desirable to put the second equation into slope-intercept form, so you can see the rise/run values that let you choose grid points on the line. That equation is y =-10/3x +4. A "rise" of -10 for a "run" of +3 will get you to (3, -6) starting from the y-intercept of (0, 4).
