Given:
Focal length: 5.0 cm
image produced: -10.0 cm
mirror equation: 1/di + 1/do = 1/f
Look for the actual distance of the object from the mirror. Solve for do.
1/do + 1/(-10) = 1/5
1/do = 1/5 + 1/10
1/do = (1/5 * 2/2) + (1/10 * 1/1)
1/do = 2/10 + 1/10
1/do = 3/10
10 = 3do
10/3 = do
3.33 = do
The distance of the object from the mirror, rounded to the nearest centimeter is 3 cm.
Answer:
See the explanation below
Explanation:
In the attached image we can see the free body diagram and forces acting on the book.
Force F, which acts to the right, the friction force which acts in the opposite direction to the movement, i.e. to the left.
The force exerted by the weight of the book that is equal to the product of the mass of the book by the gravity of the book. The normal force that is equal in magnitude to the weight of the book but in the opposite direction.
Weight = 45 * 9.8 = 441 N
Answer:
Use the method on the image and solve it.
Answer:
Its Constant so its c
Explanation:
The box is converted into the potential energy of the box.