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antoniya [11.8K]

3 years ago

10

Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he

can swing off of? You can assume aerodynamic forces prevent Spiderman from travelling greater than 30 m/s.

1 answer:

likoan [24]3 years ago

8 0

Answer:

This depends on the writers

if they want they can make spiderman deny the laws of nature

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Light in vacuum is incident on the surface of a slab of transparent material. In the vacuum the beam makes an angle of 39.9° wit

wariber [46]

Answer:

n=2.053

Explanation:

We will use Snell's Law defined as:

$n_{1}*Sin\theta_{1}=n_{2}*Sin\theta_{2}$

Where n values are indexes of refraction and $\theta$ values are the angles in each medium. For vacuum, the index of refraction in n=1. With this we have enough information to state:

$1*Sin(39.9)=n_{2}*Sin(18.2)$

Solving for $n_{2}$ yields:

$n_{2}=\frac{Sin(39.9)}{Sin(18.2)}=2.053$

Remember to use degrees for trigonometric functions instead of radians!

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3 years ago

ohms Long describes the relationship between electronic current voltage and ___

levacccp [35]

Answer:

<em>voltage</em><em> </em><em>,</em><em>current</em><em> </em><em>and</em><em> </em><em>resistance</em><em> </em>

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3 years ago

Three identical resistors have an equivalent resistance 15.6 ohm when they are connected in series. What is the resistance for e

attashe74 [19]

Answer:

$R=5.2\ \Omega$

Explanation:

In series combination, the equivalent resistance is given by :

$R_{eq}=R_1+R_2+R_3+...$

Let the identical resistors be R. We have, $R_{eq}=15.6\ \Omega$

So,

$R+R+R=15.6\\\\3R=15.6\\\\R=\dfrac{15.6}{3}\\\\R=5.2\ \Omega$

So, the resistance of each resistor is $5.2\ \Omega$ .

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2 years ago

Answer these two questions please

Grace [21]

1.The answer is True
2.The answer is False

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3 years ago

The greatest ocean depths on earth are found in the Marianas Trench near the Philippines, where the depth of the bottom of the t

kompoz [17]

Answer:

103063860 Pa

Explanation:

$\rho$ = Density of seawater = 1030 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth at which pressure is being measured = 10.2 km

The gauge pressure is given by

$p=\rho gh\\\Rightarrow p=1030\times 9.81\times 10.2\times 10^3\\\Rightarrow p=103063860\ Pa$

Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa

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3 years ago