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antoniya [11.8K]

3 years ago

10

Spiderman has a mass of 80 kg. He knows his webbing will break if it is exposed to a 200 N force. What is the maximum height he

can swing off of? You can assume aerodynamic forces prevent Spiderman from travelling greater than 30 m/s.

1 answer:

likoan [24]3 years ago

8 0

Answer:

This depends on the writers

if they want they can make spiderman deny the laws of nature

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Is the following nuclear equation balanced? <br><br> The pic is down below

vagabundo [1.1K]

Yes the equation is balanced

4 0

3 years ago

Read 2 more answers

In a double-slit experiment, if the central diffraction peak contains 13 interference fringes, how many fringes are contained wi

Ronch [10]

Answer:

Explanation:

Width of central diffraction peak is given by the following expression

Width of central diffraction peak= 2 λ D/ d₁

where d₁ is width of slit and D is screen distance and λ is wave length.

Width of other fringes become half , that is each of secondary diffraction fringe is equal to

λ D/ d₁

Width of central interference peak is given by the following expression

Width of each of bright fringe = λ D/ d₂

where d₂ is width of slit and D is screen distance and λ is wave length.

Now given that the central diffraction peak contains 13 interference fringes

so ( 2 λ D/ d₁) / λ D/ d₂ = 13

then ( λ D/ d₁) / λ D/ d₂ = 13 / 2

= 6.5

no of fringes contained within each secondary diffraction peak = 6.5

6 0

4 years ago

If you were to walk with a speed if 2m/s for 2 hours how far would you travel

olga nikolaevna [1]

So simply it to 120m/m for 120 minutes. So then you multiply 120x120 and that equals 14,400

7 0

3 years ago

Four objects are situated along the y axis as follows: a 1.99-kg object is at 2.99 m, a 2.96-kg object is at 2.57 m, a 2.43-kg o

Dominik [7]

Answer:

The center of mass for the object is $y_c = 1.063 \ m$ from the origin

Explanation:

From the question we are told that

The mass of the first object is $m_1 = 1.99 \ kg$

The position of first object with respect to origin $y_1 = 2.99 \ m$

The mass of the second object is $m_2 = 2.96 \ kg$

The position of second object with respect to origin $y_2 = 2.57 \ m$

The mass of the third object is $m_3 = 2.43 \ kg$

The position of third object with respect to origin $y_3 = 0 \ m$

The mass of the fourth object is $m_3 = 3.96 \ kg$

The position of fourth object with respect to origin $y_3 = -0.502 \ m$

Generally the center of mass of the object along the x-axis is zero because all the mass lie on the y axis

Generally the location of the center mass of the object is mathematically represented as

$y_c = \frac{m_1 * y_1 + m_2 * y_2 + m_3 * y_3 + m_4 * y_4}{m_1 + m_2 + m_3 + m_4}$

=> $y_c = \frac{1.99 * 2.99 + 2.96 * 2.57 + 2.43 * 0 + 3.96 * (-0.502)}{1.99+ 2.96 + 2.43 + 3.96}$

=> $y_c = 1.063 \ m$

3 0

3 years ago

A car driving at a constant speed of 64 mi/h travels 68 miles. How many hours did this take?

babymother [125]

64 miles/hour
Therefore 1/64 hours/mile
68 miles * 1/64 hours/mile (notice how miles cancels out)
Therefore the answer is 68/64 hours = 1.0625 hours = 1 hour 3min and 45sec.

3 0

3 years ago