An ice skater starts with a velocity of 2.25 m/s in a 50.0 degree direction. After 8.33s, she is moving 4.65 m/s in a 120 degree
direction. What is the y-component of her acceleration? PLEASE HELP
1 answer:
Answer:
jk
Explanation:
Lets decompose the initial velocity into its components:
Vi = 2.25 m/s
Vix = Vi x cos(50)
Viy = Vi x sin(50) = 2.25 x sin(50) = 1.724
Then decompose the final velocity:
Vf = 4.65
Vfx = Vf x cos(120)
Vfy = Vf x sin(120) = 4.65 x sin(120) = 4.027
After that we can use:
Vfy = Viy + ay*t
ay = (Vfy - Viy)/t
ay = (4.027 - 1.724) / 8.33
ay = 0.276
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Answer:
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Vf=10 m/s
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Explanation:
a=Vf-Vi/t
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