Question

An ice skater starts with a velocity of 2.25 m/s in a 50.0 degree direction. After 8.33s, she is moving 4.65 m/s in a 120 degree direction. What is the y-component of her acceleration? PLEASE HELP

Answer 1

Answer:

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Explanation:

Lets decompose the initial velocity into its components:

Vi  = 2.25  m/s

Vix = Vi x cos(50)

Viy = Vi x sin(50)  = 2.25 x sin(50)  = 1.724

Then decompose the final velocity:

Vf = 4.65

Vfx = Vf x cos(120)  

Vfy = Vf x sin(120)  = 4.65 x sin(120)  = 4.027

After that we can use:

Vfy = Viy + ay*t

ay = (Vfy - Viy)/t

ay = (4.027 - 1.724) / 8.33

ay = 0.276